Answer:
The augmented matrix for the system of equations is
.
Step-by-step explanation:
This system consists in three equations with three variables (
,
,
).The augmented matrix of a system of equations is formed by the coefficients and constants of the system of linear equations. In this case, we conclude that the system of equations has the following matrix:
![\left[\begin{array}{cccc}0&2&-3&1\\7&0&5&8\\4&1&-3&6\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D0%262%26-3%261%5C%5C7%260%265%268%5C%5C4%261%26-3%266%5Cend%7Barray%7D%5Cright%5D)
The augmented matrix for the system of equations is
.
Answer:
$318.17, out of state college is $161.12 cheaper per month
Step-by-step explanation:
72*24 = 1728 + 410*4 = 1728 + 1640 = 3368 + 450 = 18/12 = $318.17
8700+650*9 = 8700 + 5850 = 14550/9 = 1616.66
8500+400*9 = 8500 + 3600 = 12100 + 1000 = 13100/9 = 1455.56
1616.67 - 1455.56= $161.11 (use $161.12)
Answer:
The value of test statistic is -2.
Step-by-step explanation:
The following information is missing in the question.
The population mean is 12 minutes.
We are given the following in the question:
Population mean, μ = 12 minutes
Sample mean,
= 8 minutes
Sample size, n = 36
Population standard deviation, σ = 12 minutes
Formula:
Putting all the values, we have
The value of test statistic is -2.
For this case we have a function of the form:
y = A (b) ^ t
Where,
A: initial amount
b: growth rate
t: time
Substituting values we have:
V (t) = 2000 (1.02) ^ t
Answer:
a function that gives the total value V (t) in dollars, of the investment t years from now is:
V (t) = 2000 (1.02) ^ t
Answer:
Circumcenter = (4,0)
Circumcircle = √5
Step-by-step explanation:
The circumcentre is the point of intersection of the perpendicular bisectors of a triangle. The vertices of the triangle are equidistant to the circumcentre.
Let us assume the coordinate of the circumcentre is at O(x, y). Therefore the distance between the cirmcumcenter and the vertices are:

AO = BO, therefore
√(x² + y²-4x-2y+5) = √(x² + y² - 10x - 4y + 29)
x² + y²-4x-2y+5 = x² + y² - 10x - 4y + 29
6x + 2y = 24 (1)
BO = CO
√(x² + y² - 10x - 4y + 29) = √(x² + y² - 9x - 8y + 25)
x² + y² - 10x - 4y + 29 = x² + y² - 9x - 8y + 25
-x + 4y = -4 (2)
Multiply equation 2 by 6 and add to equation 1:
26y = 0
y=0
Put y = 0 in -x + 4y = -4
-x + 4(0) = -4
x = 4
The cicumcenter is at (4, 0)
The radius of the circumcircle = AO = BO = CO. Therefore:
