Question

{ x - 3y= -3 & x + y= 5 We are to use the graph to solve the given system of equations, then enter your solution below. I get how to draw the second equation but not the first. found slope of 1/3 & b=1. i dont understand how to graph this. I have tried different ways but keep getting it wrong. ​

Answer 1

Answer:

Solution: (3, 2)

Step-by-step explanation:

It's easier to graph when the equation of the lines are in their slope-intercept form, y = mx + b.

x - 3y = -3

-3y = -x - 3

Divide both sides by -3:

$\frac{-3y}{-3} = \frac{-x - 3}{-3}$

y = 1/3x + 1

where slope = 1/3

y-intercept = 1

x + y = 5

Subtract x from both sides to isolate y:

x - x + y = - x + 5

y = -x + 5

where slope = -1  

y-intercept, 5

I started by graphing the y-intercepts of each line. Then, I used the slope of each linear equation (rise over run) to plot the next points on the graph. In the attached screenshot of the graph, x - 3y = -3 is the blue line, while x + y = 5 is the green line. Their intersection occurs at point, (3, 2).

Therefore, the solution is (3, 2).

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