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-BARSIC- [3]
3 years ago
5

Surface roughness can be measured as either an arithmetic average (AA) or a root-mean-square (RMS) average. Which value is almos

t always greater for most surfaces?
Mathematics
1 answer:
Nat2105 [25]3 years ago
7 0

Answer:

Root-mean-square (RMS)

Step-by-step explanation:

Arithmetic average is the average of all the values of the surface peaks and valleys.

AA=\frac{\sum^n_{i=1}|y_i|}{n}

Root mean square is the root of the sum of the squares of each of the values of the surface peaks and valleys divided by the number of values

RMS=\sqrt{\frac{\sum^n_{i=1}{y_i}^2}{n}}

where n = the number of values

So, the root-mean-square RMS is always greater than the arithmetic average (AA).

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1/4

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{ -2 if x ∈ -4 < x < -3

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Step-by-step explanation:

From the graph, we have;

{ -2 if x ∈ -4 < x < -3

For the next inequality line at y = -5, we have;

1) The inequality line, starts with an open circle on the left at x = -3, which is equivalent to less than or equal to symbol, ≤ as -3 ≤ x because the point x =-3 is the left boundary.  The inequality line extends to the point x = 2, where we have a closed circle (on the right), which is equivalent to a x ≤ 2 with the 2 on the right hand side because, the 2 is the right boundary of the inequality

2) The inequality can be summarized as starting from x = -3 extends to x = 2

3) As stated in point 1) the point x = 3, we have -3 ≤ x and at point x = 2, we have x ≤ 3 which can be combined as  -3 ≤ x < 2, to give;

{ -5 if x ∈ -3 ≤ x < 2

For the next inequality line at y = 5, we have;

1) The inequality line, starts with an open circle on the left at x = 2, which is equivalent to less than or equal to symbol, ≤ as 2 ≤ x because the point x =2 is the left boundary.  The inequality line extends to the right to reach point x = 5, where we have a closed circle (on the right), which is equivalent to a x ≤ 5 inequality, with the 5 on the right hand side because, the 5 is the right boundary of the inequality

2) The inequality can be summarized as starting from x = 2 extends to x = 5

3) As stated in point 1) the point x = 2, we have 2 ≤ x and at point x = 5, we have x ≤ 5 which can be combined as  2 ≤ x < 5, to give;

[ 5 if x ∈ 2 ≤ x < 5.

7 0
3 years ago
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