Answer:
the volume of the sphere is

Step-by-step explanation:
This problem bothers on the mensuration of solid shapes, sphere and cube.
Given data
Volume of cube v = 64 cubic inches
since we are dealing with a cube the height and the radius of the sphere is same as the sides of the cube,
we know that volume of cube is expressed as



![l= \sqrt[3]{64}](https://tex.z-dn.net/?f=l%3D%20%5Csqrt%5B3%5D%7B64%7D)

also diameter d=length l
Diameter d=
Radius r =
=
= 
Height h=
we know that the volume of a sphere is given by

substituting into the formula we have

Answer:
Learning to subtract rational numbers by adding the additive inverse can be explained to your child as being the same as finding the opposite. This can even be described to your child as being a similar concept to one that they have worked with in the past where subtraction is the opposite of addition.
Additive inverse can be defined as adding a number with the opposite or the negative of that number to equal zero. The additive inverse of 1 is (-1), the additive inverse of 2 is (-2) and so on.
Example: 5 + (-5) = 0
In this example, (-5) is the additive inverse.
You can then take additive inverse one step when finding the additive inverse when subtracting rational numbers.
Example: 7 - 4 = 7 + (-4)
3 = 3
When finding the inverse, it is important to keep in mind that what you do to one side, you must do the opposite to another. In the example above, because you subtracted a positive four on one side, you are going to add a negative four to the other. This will make the equation equal on both sides.
Step-by-step explanation:
Answer:
See solutions below
Step-by-step explanation:
For what values of X are the statements below true
A. 1x>x+1
x >x+1
x-x>1
0x > 1
x > 1/0
X >∞
B) |1-x|>3
The fucntion can both be positive and negative
For the negative function
-(1-x) > 3
-1+x > 3
x > 3+1
x > 4
For the positive function
1-x > 3
-x > 3 - 1
-x > 2
x < -2
Hence the required solutions are x > 4 and x < -2
c) For the equation
|x-15| < 0
-(x - 15) < 0
-x + 15 < 0
-x < -15
x > 15
Also x-15 < 0
x < 0+15
x < 15
Hence the required solution is x > 15 and x < 15
Sedimentary rocks for the first one I think
Since the cross section is constrained to be perpendicular to the base, the shape of it is constrained to be a ...
Rectangle
_____
That rectangle may be a square, but is not required to be.