You can "plug in" the value for y from the top eq in the bottom one:
3(-2x+6) - x + 3 = 0
Simplify:
-6x + 18 - x + 3 = 0
-7x + 21 = 0
-7x = -21
x = 3
y = -2*3+6 = 0
Answer:
7+2g
Step-by-step explanation:
7 increased by means 7 +
twice Gali's height =2g
everything now becomes 7+2g
I think it might be c. but im not sure
![\bf y=r(x)=\sqrt[3]{x}\quad x= \begin{cases} -2.197\\ -1.331\\ 0\\ 1.331\\ 2.197\\ 3.375\\ 4.913 \end{cases}\implies y= \begin{cases} \sqrt[3]{-2.197}\\ \sqrt[3]{-1.331}\\ \sqrt[3]{0}\\ \sqrt[3]{1.331}\\ \sqrt[3]{2.197}\\ \sqrt[3]{3.375}\\ \sqrt[3]{4.913} \end{cases}](https://tex.z-dn.net/?f=%5Cbf%20y%3Dr%28x%29%3D%5Csqrt%5B3%5D%7Bx%7D%5Cquad%20x%3D%0A%5Cbegin%7Bcases%7D%0A-2.197%5C%5C%0A-1.331%5C%5C%0A0%5C%5C%0A1.331%5C%5C%0A2.197%5C%5C%0A3.375%5C%5C%0A4.913%0A%5Cend%7Bcases%7D%5Cimplies%20y%3D%0A%5Cbegin%7Bcases%7D%0A%5Csqrt%5B3%5D%7B-2.197%7D%5C%5C%0A%5Csqrt%5B3%5D%7B-1.331%7D%5C%5C%0A%5Csqrt%5B3%5D%7B0%7D%5C%5C%0A%5Csqrt%5B3%5D%7B1.331%7D%5C%5C%0A%5Csqrt%5B3%5D%7B2.197%7D%5C%5C%0A%5Csqrt%5B3%5D%7B3.375%7D%5C%5C%0A%5Csqrt%5B3%5D%7B4.913%7D%0A%5Cend%7Bcases%7D)
so.. .get the pair and plot them then, all you need is your calculator to get the cubic root of the provided value.
Answer:
The answer to your question is (-1, 2)
Step-by-step explanation:
Data
y = -4x - 2 Equation l
y = 2x + 4 Equation ll
Process
-Graph equation l (green line)
Plot the point (0, -2)
Starting from this point plot the point (1, -4), this point comes from the slope.
-Graph the equation ll (blue line)
Plot the point (0, 4)
Plot the point (1, 2) starting from the previous point.
-The solution is the point where the lines cross. This point is (-1, 2)