Range is the y values or ouputs
domain is inputs or x vvalues
we can use any x value
but at a certain y value, w can't go below that
find thatminimum
find the vertex
for
ax^2+bx+c
the x value of the vertex is
-b/2a
plug that in to the equaiton to get the y value
-b/2a=-(-6)/(2*2)=6/4=3/2
plug that in
2(3/2)^2-6(3/2)-9
2(9/4)-9-9
9/2-18
4.5-18
-13.5
domain=all real numbers
range=from -13.5 to positive infinity
Answer:
a(4) = 15/4
Step-by-step explanation:
Here we're told that the first term is a(1) = 30 and that the common factor r = 1/2.
Thus, the geometric sequence formula specific to this case is
a(n) = 30(1/:2)^(n-1).
What is the fourth term? Let n = 4,
a(4) = 30(1/2)^(4-1), or a(4) = 30(1/2)^(3), or a(4) = 30(1/8) = 30/8, or, in reduced form,
a(4) = 15/4.
The answer is 8, because 64÷8= 8!simple
Verrrrrrry interesting ! / / / Every multiple of an even number is another even number. When you take any whole number and the one 'before' it ... no matter which direction 'before' means .... one of the numbers is even. So their product is a multiple of an even number, and it must be another even number.
