The only way 3 digits can have product 24 is
1 x 3 x 8 = 241 x 4 x 6 = 242 x 2 x 6 = 242 x 3 x 4 = 24
So the digits comprises of 1,3,8 or 1,4,6, or 2,2,6, or 2,3,4
To be divisible by 3 the sum of the digits must be divisible by 3.
1+ 3+ 8=12, 1+ 4+ 6= 11, 2 +2 + 6=10, 2 +3 + 4=9Of those sums of digits, only 12 and 9 are divisible by 3.
So we have ruled out all but integers whose digits consist of1,3,8, and 2,3,4.
Meanwhile they must be odd they either must end in 1 or 3.
The only ones which can end in 1 are 381 and 831.
The others must end in 3.
They must be greater than 152 which is 225. So the
First digit cannot be 1. So the only way its digits can contain of1,3,8 and close in 3 is to be 813.
The rest must contain of the digits 2,3,4, and the only way they can end in 3 is to be 243 or 423.
So there are precisely five such three-digit integers: 381, 831, 813, 243, and 423.
Answer:
x=71
Step-by-step explanation:
38+x+x=180
x+x=142
2x=142
x=71
answer: 2 × 2 × 2 × 2 × 2 = 32
Step-by-step explanation:
Answer: The answer is D The difference between Shelly's and Terrence's total points
Hope this helped and brainleist please
:D
Answer:
Don't spin the barrel.
Step-by-step explanation:
Each time you spin the barrel, the probability A of finding a bullet, having two bullets in six chambers is:
For you to get shot in the second try but not the first, the barrel spin would have to stop precisely at one specific chamber: the one right before the bullets, so that probability would be:
which means that this event is half as likely as finding a bullet every time the barrel is spun. Your chances are better if you pull the trigger for the second time without spinning the barrel.
