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juin [17]
3 years ago
5

A building block is in shape of a cube with each side length of 5. what is the volume?

Mathematics
1 answer:
Alexeev081 [22]3 years ago
4 0
5×5×5 = 125..... cubed
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I asked this earlier and got no answer. Will give brainliest
Virty [35]
The area of a square is

s • s

We can also write this as

s^2

So, for any side length “s”, we can make a function, A(s), such that

A(s) = s^2

Now that we have a quadratic equation for the area of a square, let’s go ahead and solve for the side lengths of a square with a given area. In this case, 225 in^2

225 = s^2

Therefore,

s = sqrt(225)

s = 15

So, the dimensions are 15 x 15 in

6 0
4 years ago
Eli drove 856 miles on 29.4 gallons of gas what was his gas mileage rounded to the nearest mpg?
vekshin1

Answer: 29 miles per gallon.

Reasoning: 856 miles/29.4 gallons = 29.1156462585 (rounded to the nearest mile = 29)


Hope this helped!

5 0
3 years ago
Read 2 more answers
This is what I need help with can someone please give me it it's a homework I don't get
Katena32 [7]
The answer looks like it's A.
5 0
3 years ago
Help ASAP!!<br><br> i need help finding out the pattern of 3 and 4
melomori [17]

Answer:

See below.

Step-by-step explanation:

For 3, we have:

1, 3, 6, ___, 15, 21, _____, 36, _______

Let's try to determine the pattern. From 1 to 3, we added 2.

From 3 to 6, we added 3.

So, it seems that the fourth term would be to add 4, and then add 5. Let's try it:

6+4=10

10+5=15.

So, it seems we're correct. So, we will add 6, then 7, and then 8, etc. Therefore, our correct sequence would be:

1 (+2), 3 (+3), 6 (+4), 10 (+5), 15 (+6), 21 (+7), 28 (+8), 36 (+9), 45

For 4, we have:

100, _____, 64, ______, 36, 25, _______

Notice that these all are perfect squares. 10 squared is 100, 8 squared is 64, etc. Thus, we can rewrite this as:

10², _____, 8², ______, 6², 5², ______

Therefore, our blanks would be:

10², 9², 8², 7², 6², 5², 4².

Evaluated, this woul be:

100, 81, 64, 49, 36, 25, 16.

And we're done!

7 0
3 years ago
Read 2 more answers
Let X represent the amount of gasoline (gallons) purchased by a randomly selected customer at a gas station. Suppose that the me
Alexus [3.1K]

Answer:

a) 18.94% probability that the sample mean amount purchased is at least 12 gallons

b) 81.06% probability that the total amount of gasoline purchased is at most 600 gallons.

c) The approximate value of the 95th percentile for the total amount purchased by 50 randomly selected customers is 621.5 gallons.

Step-by-step explanation:

To solve this question, we use the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For sums, we can apply the theorem, with mean \mu and standard deviation s = \sqrt{n}*\sigma

In this problem, we have that:

\mu = 11.5, \sigma = 4

a. In a sample of 50 randomly selected customers, what is the approximate probability that the sample mean amount purchased is at least 12 gallons?

Here we have n = 50, s = \frac{4}{\sqrt{50}} = 0.5657

This probability is 1 subtracted by the pvalue of Z when X = 12.

Z = \frac{X - \mu}{\sigma}

By the Central Limit theorem

Z = \frac{X - \mu}{s}

Z = \frac{12 - 11.5}{0.5657}

Z = 0.88

Z = 0.88 has a pvalue of 0.8106.

1 - 0.8106 = 0.1894

18.94% probability that the sample mean amount purchased is at least 12 gallons

b. In a sample of 50 randomly selected customers, what is the approximate probability that the total amount of gasoline purchased is at most 600 gallons.

For sums, so mu = 50*11.5 = 575, s = \sqrt{50}*4 = 28.28

This probability is the pvalue of Z when X = 600. So

Z = \frac{X - \mu}{s}

Z = \frac{600 - 575}{28.28}

Z = 0.88

Z = 0.88 has a pvalue of 0.8106.

81.06% probability that the total amount of gasoline purchased is at most 600 gallons.

c. What is the approximate value of the 95th percentile for the total amount purchased by 50 randomly selected customers.

This is X when Z has a pvalue of 0.95. So it is X when Z = 1.645.

Z = \frac{X - \mu}{s}

1.645 = \frac{X- 575}{28.28}

X - 575 = 28.28*1.645

X = 621.5

The approximate value of the 95th percentile for the total amount purchased by 50 randomly selected customers is 621.5 gallons.

5 0
3 years ago
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