The probability of having a 17 is the number of ways of having 17 divided by the number of different possible outcomes.
Ways of having 17:
Die 1 Die 2 Die 3 sum
6 6 5 6+6+5 = 17
6 5 6 6+5+6 = 17
5 6 6 5+6+6 = 17
Those are the only 3 possibilities of having 17 (you can only loose 1 point).
The total number of outcomes are 6*6*6 = 216
So the chances (probability) to win is 3 / 216 = 1/72 = 0.0139
Here you go :) have a good day
1 = sin²0 + cos²0
sin²0 = 1 - cos²0
sin²0 = 1 - 11/36
sin²0 = 25/36
sin 0 = 5/6 or -5/6
In the first quadrant, the values for sin, cos and tan are positive.
sin0 = 5/6
I think it's A becaouse the answer I got was very close to the answer of A so it's A I think. Im just tying to help c:
