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Natali [406]
3 years ago
7

Determine the projection of the vector v = (−1, 6, 4 onto the vector u = (−1, 2, 4.

Mathematics
1 answer:
igomit [66]3 years ago
5 0
<span>Find the scalar and vector projections of b onto a when a = < 2,3 > and b = < 4,1 >.Scalar projection: Vector projection: </span>
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Step-by-step explanation:

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aleksley [76]

we know the x-intercept of the line is 1, recall that an x-intercept is when the graph intercepts or touches the x-axis, and when that happens, y = 0, so the point is really x = 1, y = 0, namely (1,0). We also know another point on the line, is (-2, 9).


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2 years ago
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8 0
2 years ago
Solve and explain how you did​
Sliva [168]

Answer:

We conclude that:

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Step-by-step explanation:

Given:

-\left(9x\right)^0

To determine:

Explain how to solve the expression

<u>Solving the expression</u>

-\left(9x\right)^0

Apply the exponent rule

a^0=1,\:\quad \:a\ne \:0

so the expression becomes

-\left(9x\right)^0\:=\:-1

Therefore, we conclude that:

  • -\left(9x\right)^0=-1
4 0
3 years ago
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