Determine the projection of the vector v = (−1, 6, 4 onto the vector u = (−1, 2, 4.

1 answer:

5 0

<span>Find the scalar and vector projections of b onto a when a = < 2,3 > and b = < 4,1 >.Scalar projection: Vector projection: </span>

You might be interested in

the graph represents the gallons of water tank respect to numbers of hours since it was completely filled

Sphinxa [80]

Answer:

dank memes

Step-by-step explanation:

3 0

3 years ago

To find out how many wolves lived in the valley, scientists put tracking devices on 68 wolves. Later that month, the scientists

morpeh [17]

Answer:

b. 2,924

Step-by-step explanation:

Write and solve a proportion.

24 / 1032 = 68 / x

24x = 70176

x = 2924

5 0

3 years ago

find the point-slope equation of the line perpendicular to the line y=2x+5 passing through the point (1,4). (please include solu

pishuonlain [190]

First off, let's keep in mind that perpendicular lines have negative reciprocal slopes, hmmm so what's the slope of y = 2x + 5?

well, notice, that equation is in slope-intercept form, thus $\bf y=\stackrel{slope}{2}x+5$ .

$\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}}
{2\implies \stackrel{slope}{\cfrac{2}{1}}\qquad \qquad \qquad \stackrel{reciprocal}{\cfrac{1}{2}}\qquad \stackrel{negative~reciprocal}{-\cfrac{1}{2}}}$

so, we're really looking for the equation of a line whose slope is -1/2 and runs through 1,4.

$\bf (\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad \qquad \qquad 
slope = m\implies -\cfrac{1}{2}
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-4=-\cfrac{1}{2}(x-1)$

7 0

3 years ago

Which of the following cosine functions has a period of 3π?

skelet666 [1.2K]

Answer:

y = cos 2/3 x

Step-by-step explanation:

7 0

3 years ago

Convert to cups.<br><br> 9 quarts

arsen [322]

36 cups ........................................