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Given:
Total amount = $10
Cost of loaf of bread = $3.25
Cost of cheese = $5.99 per pound
Each slice weights = 0.04 pounds.
To find:
The inequality for the number of slices that Paul can afford to buy.
Solution:
Let x be the number of slices that Paul can afford to buy.
Weight of on slice is 0.04 pounds. So, weight of x slices is 0.04x pound.
Cost of cheese = $5.99 per pound
So, total cost of cheese for x slices = $5.99 × 0.04x
Now, Paul has $10 to buy bread and cheese for sandwiches. Cost of loaf of bread is $3.25.
Divide both sides by 0.2396.
The maximum integer value of x is 28.
Therefore, the required inequity is and 28 number of slices Paul can afford to buy.
Answer:
<u>Step-by-Step Explanation:</u>
KCFmeans: Keep, Change, Flip
- Keep: the first fraction
- Change: the sign <em>from division to multiplication</em>
- Flip: the second fraction
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= <em>KCF is applied here!</em>
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