Answer:
0.066
Step-by-step explanation:
We solve this question using z score formula
z = (x-μ)/σ, where
x is the raw score
μ is the population mean
σ is the population standard deviation
For the question
mean birth weight for boys is 3.27 kg, with a standard deviation of 0.51 kg.
x = 2.5
Hence:
z = 2.5 - 3.27/0.51
z = -1.5098
Probability value from Z-Table:
P(x ≤ 2.5) =P(x < 2.5) = P(x = 2.5) =
=0.065547
Therefore, the proportion of baby boys that are born with a low birth weight is 0.066
-0,6 i believe would be the same distance from 0,0 as 0,6.
Yeah, you'd divide 1792 by 32 to get 56.
