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3 years ago

5

How do u solve ...." taylor took his children in the zoo. 2/6 of the lion packs were not well due to infection. 10 lion packs we

re well. how many lions were ill.?

1 answer:

erastova [34]3 years ago

4 0

To answer, we let x be the total number of lions in the zoo. Since, we are given that 2/6 of these lions are not well, this means that 4/6 of them are well. The given 10 is the number of lions that are well.
(4/6)(x) = 10
The value of x is 15. Therefore, 5 of the lions are ill.

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You know that 60% of students in a school are participating in a fundraiser. If between 200 and 400 students are participating,

allsm [11]

So i think in the school there may be 4800 in the school. Hope this helps

8 0

2 years ago

Here are two sets of numbers, a and b. Set a :200,104,100,160. Set b: 270,400,483,300, x. Mean of set a: mean of set b= 3:8. Wor

LenKa [72]

Given:

The given sets are:

Set a : 200, 104, 100, 160.

Set b: 270, 400, 483, 300, x.

Mean of set a: mean of set b= 3:8

To find:

The value of x.

Solution:

Formula for mean:

$Mean=\dfrac{\text{Sum of observations}}{\text{Number of observation}}$

The mean of set of a is:

$Mean=\dfrac{200+104+100+160}{4}$

$Mean=\dfrac{564}{4}$

$Mean=141$

The mean of set of b is:

$Mean=\dfrac{270+400+483+300+x}{5}$

$Mean=\dfrac{1453+x}{5}$

$Mean=\dfrac{1453+x}{5}$

It is given that,

Mean of set a: mean of set b= 3:8

$\dfrac{141}{\dfrac{1453+x}{5}}=\dfrac{3}{8}$

$\dfrac{705}{1453+x}=\dfrac{3}{8}$

$8\times 705=3\times (1453+x)$

$5640=4359
+3x$

Isolate the variable x.

$5640-4359
=3x$

$1281
=3x$

Divide both sides by 3.

$\dfrac{1281}{3}
=x$

$427
=x$

Therefore, the value of x is 427.

3 0

2 years ago

Express the following repeating decimal as a fraction in simplest form.

Ivenika [448]

Answer:

$0.\overline{369} = \frac{41}{111}$

Step-by-step explanation:

x = 0.369369369...

10x = 3.69369369...

100x = 36.9369369...

1000x = 369.369369...

1000x - x = 369

999x = 369

$x = \frac{369}{999} \\\\x = \frac{123}{333}\\\\x = \frac{41}{111}$

4 0

3 years ago

A population of insects, in thousands, can be molded using the function (t)= 1.75(0.97)x

Dominik [7]

Question:

A population of insects, in thousands, can be modeled using the function

$p(t) = 1.75(0.97)^t$ , where t is time in months. Which statement best

describes the population of insects?

A. The population is decaying at a rate of 3% each month.

B. The population is decaying at a rate of 25% each month.

C. The population is growing at a rate of 75% each month.

D. The population is growing at a rate of 97% each month.

Answer:

A. The population is decaying at a rate of 3% each month.

Step-by-step explanation:

Given

$p(t) = 1.75(0.97)^t$

Required

True statement about the function

From the options, we can see that we are to answer the question on the basis of decay and growing rates.

An exponential form is:

$y=ab^x$

Compare to $p(t) = 1.75(0.97)^t$

$b= 0.97\\$

If $b > 1$ , then $b = 1 + r$ r represents growth rate

else, $b= 1-r$ r represents decay rate

Since b < 0.97:

$0.97= 1-r$

$r = 1 - 0.97$

$r = 0.03$

$r = 3\%$

$r = 0.03$

7 0

2 years ago

Um I am very much stuck

lozanna [386]

Um. i’m pretty sure it’s just 30 feet

6 0

3 years ago

Read 2 more answers