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aleksklad [387]
3 years ago
11

Martha earns $12.47 per hour. John makes 3 times as much as Martha. How much does John earn per hour?

Mathematics
2 answers:
solmaris [256]3 years ago
5 0

The answer is C.37.41

maks197457 [2]3 years ago
5 0
It's C. $37.41 that's is ur answer
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tangare [24]

Answer:

oouu I'm in 7th grade science and I already did this I can help!

3 0
3 years ago
Brian bought 215 pounds of strawberries. In the afternoon his brother ate 56 of the strawberries. How many pounds of strawberrie
Art [367]

Hi there!

Step By Step:

We know that 215 pounds are about 215 strawberries since every strawberry are about 1 pound.

Let think about this... 215 pounds are 215 strawberries.

If his brother ate 56 of the strawberries, it means that his brother ate 56 pounds of the strawberry.

We can also think like this... 56/215

Final Result: 56 pound sof strawberries.

3 0
3 years ago
|2x-3|=2 please answer this by Wednesday. I have no idea how to solve this. I wasn't paying attention
Sholpan [36]

Answer:

x=2.5

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Suppose that two teams are playing a series of games, each of which is independently won by team A with probability p and by tea
Lady_Fox [76]

Answer:

4 games played = 1/56

5 games played = 5/56

6 games played = 15/56

7 games played = 35/56

Step-by-step explanation:

The probability of each time winning is 0.5

So there are a couple of ways the series could go.

  1. Team A could win all first 4 matches. We can depict this as A-A-A-A
  2. Team A could win 4, while having lost 1.  Lets depict this a A-B-A-A-A
  3. Team A could win 4, while having lost 2. A-B-B-A-A-A
  4. Team A could win 4, while having lost 3. A-B-B-B-A-A-A

These 4 possibilities could be repeated with B winning as well. It should be noted that these are the only ways for the series to end. We find the number of permutations of each possibility above to find their probability.

I advise you to study 'how to permute identical objects' for this.

These permutations are stated below:

1. 4!/4! = 1

2. \frac{5!}{4! * 1!} = 5

3 \frac{6!}{4! * 2!} = 15

4 \frac{7!}{4! * 3!} = 35

These are they ways A or B could win. The total is 1+5+15+35 = 56. The answer given thus reflects the possibilities.

4 0
4 years ago
X + 3 ? 3 = x what factor do I use in between 3 and 3
Otrada [13]

Answer:

1 or 3

Step-by-step explanation:

factors of 3 r 1 and 3

that's why 3 is a prime number

4 0
3 years ago
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