3 years ago

Simplify (a+7) + (3a+4)

Mathematics

1 answer:

elena-14-01-66 [18.8K]3 years ago

3 0

Answer:

= 4a + 11

Step-by-step explanation:

a+7+3a+4

Combine Like Terms:

= a + 7 + 3a + 4

= (a + 3a) + (7 + 4)

= 4a + 11

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Angles D and G are complementary. What statement must always be true about angles D and G?

nikklg [1K]

Answer:

They will never intersect. I'm pretty sure that is right

4 0

3 years ago

Distribute and Combine Like Terms 11(2t - 4) + 6t - 6

Nutka1998 [239]

It’s actually 28t - 10

11(2t-4)+6t-6
22t-4+6t-6 add 22t and 6t
28t-4-6 combine -4 & -6
28t-10

5 0

3 years ago

Which expression is equivalent to -9a-10-6a+7−9a−10−6a+7

Gwar [14]

Answer:

−30a−6

Step-by-step explanation:

Let's simplify step-by-step.

−9a−10−6a+7−9a−10−6a+7

=−9a+−10+−6a+7+−9a+−10+−6a+7

Combine Like Terms:

=−9a+−10+−6a+7+−9a+−10+−6a+7

=(−9a+−6a+−9a+−6a)+(−10+7+−10+7)

=−30a+−6

BRAINLIEST. if you don't mind.

6 0

3 years ago

I need to figure this out for a quiz in APEX. I can get the rest if I understand how to do this one.

KIM [24]

The answer is b
(-1,3,5)

Hope this helps!

8 0

3 years ago

A car traveled 330 miles during a 5½ hour period. If the speed at which the car traveled can be represented in the equation d=rt

Alina [70]

Answer:

The car was travelling at a speed of 60 miles per hour.

Step-by-step explanation:

Given:

Distance traveled = 330 miles

Time Period = $5 \frac12\ hr$

we need to find the speed of the car .

Solution:

Time Period = $5 \frac12\ hr$

Now we can say that;

$\frac12\ hr =0.5\ hr$

So Time period = $5+0.5 =5.5\ hr$

Now we know that;

Distance traveled $(d)$ is equal to Speed $(r)$ multiplied by Time Period $(t)$ .

framing in equation form we get;

$d=rt\\\\330 =r\times 5.5$

Dividing both side by 5.5 we get;

$\frac{330}{5.5}=\frac{5.5r}{5.5}\\\\r = 60\ mi/hr$

Hence The car was travelling at a speed of 60 miles per hour.

6 0

3 years ago