<span>More please help me solve the problem
The stars have different brightness. The brightest stars are Grade 1 and the least degree luimnoase stars 6. The brightness of the stars shrinks 2.5 times with the passing from one grade to another. Whenever the stars are brighter Grade 1, Grade 6 than the stars?</span>
Answer:
B
Step-by-step explanation:
180-118=42 so angle c=42
add 42 +76 =138
in a triangle all degrees ad up to 180 so
subtract 138 from 180=42
The correct answer is: [C]: " c(x) = –8x²<span> + 3x – 5 " .
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The quadratic function takes the form of:
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" f(x) = ax</span>² + bx + c " .
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Answer choice: [C]: " c(x) = –8x² + 3x – 5 " ;
is the only answer choice provided that takes that form of the quadratic function:
" f(x) = ax² + bx + c " :
in which: " a = -8 " ; " b = 3 " ; " c = -5 " .
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It equals 23 degrees Fahrenheit. So -5c=23f
<span>perpendicular slope :
m1 * m2 = -1
1/2 * m2 = -1
m2 = -2
y = -2x + b
2 = -4 +b
b = 6
y = -2x + 6
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