Question

If both the zeroes of a polynomial x2+4x+2p are real and equal then find the value of p.

Answer 1

Answer:

p = 2

Step-by-step explanation:

If both zeroes at equal, they must be the negative half of the second term. As this term is 4, $-\frac{4}{2} =-2$. This means that each of the zeroes must be -2. This means that the polynomial must be  $(x+2)^2$

This simplifies to $x^2+4x+4$

From the intial problem, we can set up an equation and solve for p. $2p=4\\\\p=2$