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liraira [26]
3 years ago
5

Li Na is going to plant 63tomato plants and 81 rhubarb plants.

Mathematics
1 answer:
Ivan3 years ago
6 0

The greatest number of rows Li Na can plant is 9

<h3><u>Solution:</u></h3>

Given that Li Na is going to plant 63 tomato plants and 81 rhubarb plants

Li Na would like to plant the plants in rows where each row has the same number of tomato plants and each row has the same number of rhubarb plants

<em><u>To find: greatest number of rows Li Na can plant</u></em>

To find the greatest number of rows of plants we have to list the factors of 63 and 81 and find the greatest common one

The factors of 63 are: 1, 3, 7, 9, 21, 63

The factors of 81 are: 1, 3, 9, 27, 81

Then the greatest common factor of 63 and 81 is 9

Thus greatest number of rows Li Na can plant is 9

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The midpoint of y and 31 is -5. what is y
pochemuha
Y = -41.
EXPLANATION.
if -5 is the midpoint, it must be -5 + 36.
Because there is 36 numbers between 31 and -5.
So -5 + 36 = -41.
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3 years ago
Whats the domain of this function?
nika2105 [10]

Answer:

to reflect the line and record readings

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3 years ago
Alberto ran a race at a speed of 9 meters per second. Omar had a 6 meter head start and ran at a speed of 7 meters per second. B
zloy xaker [14]

Answer: Alberto run 27 meters.

Time taken By Alberto=3 seconds


Step-by-step explanation:

Let d be the distance Alberto ran to catch Omar.

Then, distance ran by Omar=x-6

Also, \text{Time}=\frac{\text{Distance}}{\text{Speed}}

Since, both started running at the same time.

Time taken By Alberto=\frac{x}{9}

Time taken By Omar=\frac{x-6}{7}

Now, at the point they meet time taken by both is equal.

\frac{x}{9}=\frac{x-6}{7}\\\Rightarrow\ 7x=9(x-6)\\\Rightarrow7x=9x-54\\\Rightarrow9x-7x=54\\\Rightarrow\ 2x=54\\\Rightarrow\ x=27

Hence, Alberto run 27 meters.

Time taken By Alberto=\frac{27}{9}=3 seconds

6 0
3 years ago
mr.browns salary is 32,000 and imcreases by $300 each year, write a sequence showing the salary for the first five years when wi
chubhunter [2.5K]

Hello!  

We have the following data:  

a1 (first term or first year salary) = 32000

r (ratio or annual increase) = 300

n (number of terms or each year worked)  

We apply the data in the Formula of the General Term of an Arithmetic Progression, to find in sequence the salary increases until it exceeds 34700, let us see:

formula:

a_n = a_1 + (n-1)*r

* second year salary

a_2 = a_1 + (2-1)*300

a_2 = 32000 + 1*300

a_2 = 32000 + 300

\boxed{a_2 = 32300}

* third year salary

a_3 = a_1 + (3-1)*300

a_3 = 32000 + 2*300

a_3 = 32000 + 600

\boxed{a_3 = 32600}

* fourth year salary

a_4 = a_1 + (4-1)*300

a_4 = 32000 + 3*300

a_4 = 32000 + 900

\boxed{a_4 = 32900}

* fifth year salary

a_5 = a_1 + (5-1)*300

a_5 = 32000 + 4*300

a_5 = 32000 + 1200

\boxed{a_5 = 33200}

We note that after the first five years, Mr. Browns' salary has not yet surpassed 34700, let's see when he will exceed the value:

* sixth year salary

a_6 = a_1 + (6-1)*300

a_6 = 32000 + 5*300

a_6 = 32000 + 1500

\boxed{a_6 = 33500}

* seventh year salary

a_7 = a_1 + (7-1)*300

a_7 = 32000 + 6*300

a_7 = 32000 + 1800

\boxed{a_7 = 33800}

*  eighth year salary

a_8 = a_1 + (8-1)*300

a_8 = 32000 + 7*300

a_8 = 32000 + 2100

\boxed{a_8 = 34100}

* ninth year salary

a_9 = a_1 + (9-1)*300

a_9 = 32000 + 8*300

a_9 = 32000 + 2400

\boxed{a_9 = 34400}

*  tenth year salary

a_{10} = a_1 + (10-1)*300

a_{10} = 32000 + 9*300

a_{10} = 32000 + 2700

\boxed{a_{10} = 34700}

we note that in the tenth year of salary the value equals but has not yet exceeded the stipulated value, only in the eleventh year will such value be surpassed, let us see:

*  eleventh year salary

a_{11} = a_1 + (11-1)*300

a_{11} = 32000 + 10*300

a_{11} = 32000 + 3000

\boxed{\boxed{a_{11} = 35000}}\end{array}}\qquad\checkmark

Respuesta:

In the eleventh year of salary he will earn more than 34700, in the case, this value will be 35000

________________________

¡Espero haberte ayudado, saludos... DexteR! =)

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14. You play a video game for 15 m
Natasha2012 [34]

Answer:

11 because 165÷25=11 so yeah

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