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Aleks [24]
3 years ago
13

Listed below are amounts (in millions of dollars) collected from parking meters by a security company in a certain city. A large

r data set was used to convict 5 members of the company of grand larceny.
a) Find the mean and median for each of the two samples and then compare the two sets of results.
b) Do the limited data listed here show evidence of stealing by the security company's employees?
Security Company Other Companies1.6; 1.51.8; 2.11.6; 1.91.8; 2.21.7; 1.91.2; 1.71.1; 2.11.2; 2.21.2; 2.21.5; 1.8
Mathematics
1 answer:
irina1246 [14]3 years ago
8 0

Answer:

The correct options are;

B) The mean and median for the security company are both lower than the mean and the median for the collections performed by other companies

B) Since the security company appear to have collected lower revenue than other companies, there is some evidence of stealing by the security company's employees

Step-by-step explanation:

We use the acronym SC for the security company and OC for the other company

SC OC

1.6 1.5

1.8 2.1

1.6 1.9

1.8 2.2

1.7 1.9

1.2 1.7

1.1 2.1

1.2 2.2

1.2 2.2

1.5 1.8

∑x    14.7   19.6

The mean is given by  ∑x/n

n = 10

               SC        OC

∴ Mean 1.47      1.96

The median is the \frac{n + 1}{n} th  \ term

Hence

               SC         OC

Median 1.55         2

Therefore, the mean and median for the security company are both lower than the mean and the median for the collections performed by other companies.

b) Since the security company appear to have collected lower revenue than other companies, there is some evidence of stealing by the security company's employees.

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svetlana [45]
X^(3/5) = 1.84

x^(3/5) = (1.84)

Raise both sides of the equation to (5/3).  

This is so that on the side with x,  3/5 * 5/3 = 1.

(x^3/5 )^5/3 = (1.84)^(5/3)

x^(3/5  *  5/3) = 1.84^(5/3)

x^1 = 1.84^(5/3)
 
x = 1.84^(5/3)

But remember we are solving for x^2.

x = 1.84^(5/3)

x^2 = (1.84^(5/3))^2

x^2 =  1.84^(5/3  *2 )

x^2 =  1.84^(10/3)

Use a calculator here.

x^2 =  1.84^(10/3) ≈ 7.63

Option A.

Cheers!
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