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Daniel [21]
3 years ago
14

Can anyone help me to understand how u add,subtract,multiply and divide fractions like explain how u do it using an example:) Pl

z and thx
Mathematics
1 answer:
Elden [556K]3 years ago
4 0
Adding fractions:
Lets say you have two fractions like 1/2 and 1/3. To add them, you have to make the denominator the same. So we find the least common multiple of 2 and 3, which is 6, so we multiple 1/2 by 3/3 so we have 3/6 without changing the value, and we multiple 1/3  by 2/2 to have 2/6. Then we add the numerators and have 5/6.

Subtraction fractions:
Same thing as adding, just subtracting instead.
Both need to make sure you have the same denominator.

Multiplying fractions:
This is the most simple. All you do is multiply the numerators and the denominators. So if you have 5/6 and 3/4, you multiply the numerators to have 15, the denominators to have 24, and so you have 15/24, simplified to 5/8.

Dividing fractions:
If you have 5/6 divided by 3/4, you flip the 3/4 to 4/3, and you multiply that with 5/6.
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3 years ago
Evaluate the expression. 5 x (-6 / -1 + -10)
kotykmax [81]

Answer:

-20

Step-by-step explanation:

5 * (-6 / -1+ -10)

According to PEMDAS, we need to do the math in the parentheses first.

-6 / -1 + -10

Applying PEMDAS to the inside of the parentheses, then we have to divide -6 by -1, where we would get 6.

6 + -10

Adding a negative is the same as subtracting, so adding negative 10 is the same as subtracting 10.

6 - 10

Subtracting, we get 6 - 10 = -4 and we're left with:

5 * (-4)

Multiplying, <u>our final answer is -20.</u>

Hope this helps!

8 0
2 years ago
Sec (a) + tan (a) = sec (a) – tan (a)
Mariulka [41]

Answer:

a = π n for n element Z

Step-by-step explanation:

Solve for a:

sec(a) + tan(a) = sec(a) - tan(a)

Subtract sec(a) - tan(a) from both sides:

2 tan(a) = 0

Divide both sides by 2:

tan(a) = 0

Take the inverse tangent of both sides:

Answer:  a = π n for n element Z

7 0
3 years ago
Help. I’m supposed to move the coordinates by the way.
DENIUS [597]

The coordinates of point D is given as

(x,y)=(-4,1)

Since the question asks to get two points sharing the same x-coordinate as D, we will move the points along the y-axis.

Therefore, we will add and subtract 7 units from the y-axis.

Let the first point be A. The coordinates for A will be

\begin{gathered} (x,y)=(-4,1+7) \\ (x,y)=(-4,8) \end{gathered}

Let the second point be B. The coordinates will be

\begin{gathered} (x,y)=(-4,1-7) \\ (x,y)=(-4,-6) \end{gathered}

We can plot the graph as shown below:

8 0
1 year ago
HELP ASAP I WILL GIVE YOU BRAINLEAST<br><br> WHAT IS THE EQUATION OF THE GRAPH?
siniylev [52]

Problem 1 (on the left)

It appears we have an exponential function curve through the points (0,4) and (1,7)

The general exponential function is of the form

y = a*b^x

The value of 'a' is the y intercept or initial value. So a = 4

Plug in (x,y) = (1,7) to help solve for b

y = a*b^x

y = 4*b^x

7 = 4*b^1

7 = 4b

b = 7/4 = 1.75

Therefore, the function is y = 4*(1.75)^x

  • Plug in x = 0 and you should get y = 4.
  • Plug in x = 1 and you should get y = 7

These two facts help confirm we have the correct exponential equation.

<h3>Answer: y = 4*(1.75)^x</h3>

===========================================================

Problem 2 (on the right)

The steps will follow the same idea as the previous question.

The exponential curve goes through (-1, 120) and (0,40)

We have a = 40 this time due to the y intercept (0,40)

Plug in the coordinates of the other point to find b

y = a*b^x

y = 40*b^x

120 = 40*b^(-1)

120 = 40/b

120b = 40

b = 40/120

b = 1/3

<h3>Answer:  y = 40*(1/3)^x</h3>
3 0
2 years ago
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