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Stels [109]
2 years ago
9

On a scale drawing, 9 inches represents 11 miles. How many inches represent 55 miles?

Mathematics
1 answer:
Elodia [21]2 years ago
6 0

Answer: you will get 45

Step-by-step explanation:

If you do 9x5=45 and 11x5=55

So the answer would be 45

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Ind the value of x which satisfies the equation 2x - (4 - x) = 5 - X​
mina [271]

Answer:

2,25

Step-by-step explanation:

2x-4+x=5-x

2x+x+x=5+4

4x=9 |÷4

x=2,25

8 0
3 years ago
Read 2 more answers
The drawing below is of a regular pentagon. The measure for each interior angle in a regular pentagon is 108°. Angle A is supple
myrzilka [38]

Answer:

  • 72°

Step-by-step explanation:

<u>The interior and exterior angles are supplementary:</u>

  • A + 108° = 180°
  • A = 180° - 108°
  • A = 72°
6 0
2 years ago
What is 2x - y = last question
Elza [17]

Answer:

Step-by-step explanation:

Let's simplify step-by-step.

2x−y

There are no like terms.

Answer:

=2x−y

8 0
3 years ago
Read 2 more answers
• A researcher claims that less than 40% of U.S. cell phone owners use their phone for most of their online browsing. In a rando
antiseptic1488 [7]

Answer:

We failed to reject H₀

Z > -1.645

-1.84 > -1.645

We failed to reject H₀

p > α

0.03 > 0.01

We do not have significant evidence at a 1% significance level to claim that less than 40% of U.S. cell phone owners use their phones for most of their online browsing.

Step-by-step explanation:

Set up hypotheses:

Null hypotheses = H₀: p = 0.40

Alternate hypotheses = H₁: p < 0.40

Determine the level of significance and Z-score:

Given level of significance = 1% = 0.01

Since it is a lower tailed test,

Z-score = -2.33 (lower tailed)

Determine type of test:

Since the alternate hypothesis states that less than 40% of U.S. cell phone owners use their phone for most of their online browsing, therefore we will use a lower tailed test.

Select the test statistic:  

Since the sample size is quite large (n > 30) therefore, we will use Z-distribution.

Set up decision rule:

Since it is a lower tailed test, using a Z statistic at a significance level of 1%

We Reject H₀ if Z < -1.645

We Reject H₀ if p ≤ α

Compute the test statistic:

$ Z =  \frac{\hat{p} - p}{ \sqrt{\frac{p(1-p)}{n} }}  $

$ Z =  \frac{0.31 - 0.40}{ \sqrt{\frac{0.40(1-0.40)}{100} }}  $

$ Z =  \frac{- 0.09}{ 0.048989 }  $

Z = - 1.84

From the z-table, the p-value corresponding to the test statistic -1.84 is

p = 0.03288

Conclusion:

We failed to reject H₀

Z > -1.645

-1.84 > -1.645

We failed to reject H₀

p >  α

0.03 > 0.01

We do not have significant evidence at a 1% significance level to claim that less than 40% of U.S. cell phone owners use their phones for most of their online browsing.

8 0
3 years ago
Can someone do my hw for me
IrinaVladis [17]

Answer:

depends on what the homework is

6 0
2 years ago
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