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e-lub [12.9K]
3 years ago
8

Please help me with number 26, thank you

Mathematics
1 answer:
Umnica [9.8K]3 years ago
8 0
It's not prime and it can be timed by 2
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What is the volume of the prism? Use the formula V equals B h. Enter the answer in the box.
MakcuM [25]

Answer:

29.4\ cm^3

Step-by-step explanation:

b = 4 × 3.5 = 14 cm²

h = 2,1 cm

then

V=b\times h

   =14\times2.1

   =29.4\ cm^3

7 0
2 years ago
Read 2 more answers
What is the mean of the values in the dot plot?<br><br><br><br> Enter your answer in the box.
ziro4ka [17]

Answer:

The mean is 19.5

Step-by-step explanation:

You have to add all of the numbers up then divide by how many numbers there are.

Ex: 5, 5, 6, 7

add them up and you get 23

Divide 23 by how many numbers you have, which in this case, is 4

The answer to this example would be 5.75

4 0
3 years ago
The purpose of a battery in a circuit is to _____.
skelet666 [1.2K]

Answer:

Increase the potential of charges in the circuit

Step-by-step explanation:

Hope this is correct

HAVE A GOOD DAY!

7 0
3 years ago
a contractor is on top of 167 ft Tower looking down at a 37 degree angle of depression at a package attached to a rope on the gr
ArbitrLikvidat [17]

Using trigonometry ratio

\sin 37^0=\frac{167}{x}\begin{gathered} 0.6018\text{ = }\frac{167}{x} \\ 0.6018x\text{ = 167} \\ x\text{ = }\frac{167}{0.6018}\text{ = 277.5ft} \end{gathered}

x = 277.5 ft

3 0
1 year ago
Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 144 millimeters,
valentinak56 [21]

Answer:

The probability that the sample mean would differ from the population mean by more than 2.6 mm is 0.0043.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and appropriately huge random samples (n > 30) are selected from the population with replacement, then the distribution of the sample  means will be approximately normally distributed.

Then, the mean of the distribution of sample mean is given by,

\mu_{\bar x}=\mu

And the standard deviation of the distribution of sample mean  is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

The information provided is:

<em>μ</em> = 144 mm

<em>σ</em> = 7 mm

<em>n</em> = 50.

Since <em>n</em> = 50 > 30, the Central limit theorem can be applied to approximate the sampling distribution of sample mean.

\bar X\sim N(\mu_{\bar x}=144, \sigma_{\bar x}^{2}=0.98)

Compute the probability that the sample mean would differ from the population mean by more than 2.6 mm as follows:

P(\bar X-\mu_{\bar x}>2.6)=P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}} >\frac{2.6}{\sqrt{0.98}})

                           =P(Z>2.63)\\=1-P(Z

*Use a <em>z</em>-table for the probability.

Thus, the probability that the sample mean would differ from the population mean by more than 2.6 mm is 0.0043.

8 0
3 years ago
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