Answer:
The list that would be helpful in this situation would be a list of people in the airport
Hope This Helps!!!
Answer:
In Python:
def sumLastPart(n,thelist):
sumlast = 0
lent = len(thelist)
lastN = lent - n
for i in range(lastN,lent):
sumlast+=thelist[i]
return sumlast
Explanation:
This defines the function
def sumLastPart(n,thelist):
This initializes the sum to 0
sumlast = 0
This calculates the length of the list
lent = len(thelist)
This calculates the index of the last n digit
lastN = lent - n
This iterates through the list and adds up the last N digits
<em> for i in range(lastN,lent):</em>
<em> sumlast+=thelist[i]</em>
This returns the calculated sum
return sumlast
Int count(int num)
if num==0 return 0;
return (n&1)+count (n/2)
<u>Threat </u>is some danger that can exploit a vulnerability.
<h3>What is Threat?</h3>
Threat is seen as Anything that can be able to take advantage of a vulnerability, intentionally as well as accidentally, and take or damage, the asset of a person.
Note that a threat is that which a person or firm is protect against and Vulnerability is seen as Weaknesses.
Therefore, <u>Threat </u>is some danger that can exploit a vulnerability.
Learn more about vulnerability from
brainly.com/question/25633298
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I dont really understand what you want to do but im gonna answer it as if I understood it.
If x is 10 and y is 20 then y is larger than x
