The value of the 5 in money is <em>5 cents</em>.
First, let’s start off by removing the two that don’t a a brother or sister. That leaves 10 people who do. The we calculate the access answers. They go in the middle. It’s 6. Then we have one more that has only a sister, put that at the S side. Then we have 3 more left that have only a brother, put them on the B side. Then you have 10 dots on the diagram for the 10 peoples that have a brother and/or a sister.
To conclude:
3 on B
6 in between
1 on S
Answer:
462ways
Step-by-step explanation:
This Is a combination problem, we we are expected to determine the number of possible ways of selecting the numbers of staffs for a business trip
C(n, r) were n= 11
r=5
C(n, r) = n!/(n-r)! r!
C(n, r) = 11!/(11-5)! 5!
C(n, r) = 11!/(6)! 5!
C(n, r) = 11*10*9*8*7*6!/(6)! 5*4*3*2*1
C(n, r) = 11*10*9*8*7/5*4*3*2*1
C(n, r) = 55440/120
C(n, r) = 462
The number of possible ways is 462
(4*105)-(1.4*105)
420-145.6
The answer is 274.4
