A, C, D, E . all of them are true.
the number of elements in the union of the A sets is:5(30)−rAwhere r is the number of repeats.Likewise the number of elements in the B sets is:3n−rB
Each element in the union (in S) is repeated 10 times in A, which means if x was the real number of elements in A (not counting repeats) then 9 out of those 10 should be thrown away, or 9x. Likewise on the B side, 8x of those elements should be thrown away. so now we have:150−9x=3n−8x⟺150−x=3n⟺50−x3=n
Now, to figure out what x is, we need to use the fact that the union of a group of sets contains every member of each set. if every element in S is repeated 10 times, that means every element in the union of the A's is repeated 10 times. This means that:150 /10=15is the number of elements in the the A's without repeats counted (same for the Bs as well).So now we have:50−15 /3=n⟺n=45
Answer:
105 km
Step-by-step explanation:
Written as a proportion, the ratio of km to cm will be the same for both distances:
(x km)/(17.5 cm) = (15 km)/(2.5 cm)
x km = (15 km)(17.5/2.5) = 105 km
105 actual kilometers are represented by 17.5 cm on the map.
we have the function
Part a
For t=7
substitute in the given function
For t=14
For t=21
For t=28
For t=35
Observation: The values of E varies from -1 to 1, including the zero
Part B
Remember that
The Period goes from one peak to the next
so
Period=2pi/B
B=pi/14
Period=(2pi)/(pi/14)=2pi*14/pi=28
<h2>the period is 28 days</h2>
Answer:
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