![\: \: \:](https://tex.z-dn.net/?f=%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20)
![\pink{ 5.37}](https://tex.z-dn.net/?f=%20%5Cpink%7B%205.37%7D)
- <u>To visualize 5.3</u><u>7</u><u> more accurately, divide line segment between 5.37 and 5.38 in ten equal parts. 5.3</u><u>7</u><u> lies between 5.377 and 5.378.</u>
- <u>Again </u><u>use </u><u>divide</u><u> above portion between 5.377 and 5.378 into 10 equal parts, which shows 5.3</u><u>7</u><u> is located closer to 5.3778 than to 5.3777</u><u> </u><u>so </u><u>we </u><u>can </u><u>get </u><u>the </u><u>answer</u>
<h2><u>hope</u><u> it</u><u> helps</u></h2>
Convert any mixed numbers to fractions.
Then your initial equation becomes:
−
1
3
×
18
5
Applying the fractions formula for multiplication,
=
−
1
×
18
3
×
5
=
−
18
15
Simplifying -18/15, the answer is
Answer:
i dont know the answer hihihihi
Let, x = The cost of an apple
y = The cost of a peach
6x + 9y = 7.86 - - - - - - - - 1
4x + 5y = 4.82 - - - - - - - - 2
From equation 2,
4x =4.82 - 5y
x= (4.82 - 5y) ÷ 4 - - - - - - - 3
Substitute 3 into 1,
6x + 9y = 7.86
6 [(4.82 - 5y) ÷ 4] + 9y = 7.86
(28.92 - 30 y) ÷4 + 9y = 7.86
28.92 - 30y + 36y = 31.44
6y=2.52
y= 0.42
Substitute y = 0.42 into 2
4x + 5y= 4.82
4x + 5 (0.42) = 4.82
4x + 2.1 = 4.82
4x= 2.72
x= 0.68.
Thus, an apple costs $ 0.68 and a peach costs $ 0.42.
Answer:
The value of
is 432.
Step-by-step explanation:
Let be the following system of equations:
(1)
(2)
Then, we solve both for
and
:
From (1):
![2\cdot x + 3\cdot y = 12](https://tex.z-dn.net/?f=2%5Ccdot%20x%20%2B%203%5Ccdot%20y%20%3D%2012)
![2\cdot x = 12- 3\cdot y](https://tex.z-dn.net/?f=2%5Ccdot%20x%20%3D%2012-%203%5Ccdot%20y)
![x = 6 - \frac{3}{2}\cdot y](https://tex.z-dn.net/?f=x%20%3D%206%20-%20%5Cfrac%7B3%7D%7B2%7D%5Ccdot%20y)
(1) in (2):
![\left(6-\frac{3}{2}\cdot y \right)\cdot y = 6](https://tex.z-dn.net/?f=%5Cleft%286-%5Cfrac%7B3%7D%7B2%7D%5Ccdot%20y%20%5Cright%29%5Ccdot%20y%20%3D%206)
![6\cdot y-\frac{3}{2}\cdot y^{2} = 6](https://tex.z-dn.net/?f=6%5Ccdot%20y-%5Cfrac%7B3%7D%7B2%7D%5Ccdot%20y%5E%7B2%7D%20%3D%206)
![\frac{3}{2}\cdot y^{2}-6\cdot y + 6 = 0](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B2%7D%5Ccdot%20y%5E%7B2%7D-6%5Ccdot%20y%20%2B%206%20%3D%200)
The roots of the polynomial are determined by the Quadratic Formula:
![y_{1} = y_{2} = 2](https://tex.z-dn.net/?f=y_%7B1%7D%20%3D%20y_%7B2%7D%20%3D%202)
By (1):
![x = 6 - \frac{3}{2}\cdot (2)](https://tex.z-dn.net/?f=x%20%3D%206%20-%20%5Cfrac%7B3%7D%7B2%7D%5Ccdot%20%282%29)
![x = 3](https://tex.z-dn.net/?f=x%20%3D%203)
If we know that
and
, then the final value is:
![z = 8\cdot x^{3}+27\cdot y^{3}](https://tex.z-dn.net/?f=z%20%3D%208%5Ccdot%20x%5E%7B3%7D%2B27%5Ccdot%20y%5E%7B3%7D)
![z = 8\cdot 3^{3}+27\cdot 2^{3}](https://tex.z-dn.net/?f=z%20%3D%208%5Ccdot%203%5E%7B3%7D%2B27%5Ccdot%202%5E%7B3%7D)
![z = 432](https://tex.z-dn.net/?f=z%20%3D%20432)
The value of
is 432.