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NemiM [27]
3 years ago
11

A rectangular blanket is 70 inches long and 48 inches wide. Kim wants to put a border along the edge of the blanket. What is the

least amount of ribbon Kim need to go around the edge of the blanket
Mathematics
1 answer:
prisoha [69]3 years ago
3 0
Kim needs a ribbon that is 6,720 inches long,because 48×70=3360.Then,since there are 4 sides,not just 2,you would have to multiply 3360×2 and that will give you 6720.
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3 0
4 years ago
Read 2 more answers
What is the maximum area for a rectangle whose perimeter is 48 meters?
MakcuM [25]

Answer:

12m²

Step-by-step explanation:

For a rectangle, with length L and width W,

the perimeter is given as

Perimeter,

P = (2 x Length)  + (2 x Width)

P = 2L + 2W

It is given that the perimeter is 48, hence

48 = 2L + 2W   (divide both sides by 2)

24 = L + W

or

L = 24 - W -----> eq 1

Also realize that the Area of a Rectangle is given by

A = L x W  -----> eq 2

Substituting eq 1 into eq 2,

A = (24 - W) x W

A = -W² + 24W

Recall that for a quadratic equation y = ax² + bx + c, the maxima or minima is given by y(max) =  -b/2a

In this case, b = 24 and a = -1

-b/2a = -24/[ 2(-1) ] = 12

Hence for A to be maximum A(max) = 12m² (Answer)

5 0
4 years ago
3x-5+2x=15+4x-5 how do I solve this step by step
bezimeni [28]
3x - 5 + 2x = 15+ 4x - 5
5x - 5 = 10 + 4x
5x - 5 + 5 = 10 +5 +4x
5x = 4X + 15
5x - 4x = 4x - 4x + 15
x = 15 
6 0
4 years ago
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