Slope = (y2 - y1) / (x2 - x1)
(-9,6)....x1 = -9 and y1 = 6
(-3,9)...x2 = -3 and y2 = 9
now we sub and solve
slope = (9 - 6) / (-3 - (-9) = 3 / (-3 + 9) = 3/6 = 1/2 <=
Answer:
Step-by-step explanation:
The difference is 130-150 = -20, a decrease.
-20/150 ≅ -0.133, a decrease of 13.3%
Answer:
The figure is attached and the total distance is 1031 feet.
Step-by-step explanation:
The graph is indicated in the attached figure.
For calculation of distance consider following
Point Flagpole is (0,0)
Point Clue1 is (0,5)
Point Clue2 is (6,0)
Point Clue3 is (0,-5)
So the distance is calculated as follows
![d_{T}=[d_{FP\ to\ Clue1}+d_{Clue1\ to\ Clue2}+d_{Clue2\ to\ Clue3}]*distance\ per\ unit\\d_{T}=[\sqrt{(Clue1_x-FP_x)^2+(Clue1_y-FP_y)^2}+\sqrt{(Clue2_x-Clue1_x)^2+(Clue2_y-Clue1_y)^2}+\sqrt{(Clue3_x-Clue2_x)^2+(Clue3_y-Clue2_y)^2}]**distance\ per\ unit\\](https://tex.z-dn.net/?f=d_%7BT%7D%3D%5Bd_%7BFP%5C%20to%5C%20Clue1%7D%2Bd_%7BClue1%5C%20to%5C%20Clue2%7D%2Bd_%7BClue2%5C%20to%5C%20Clue3%7D%5D%2Adistance%5C%20per%5C%20unit%5C%5Cd_%7BT%7D%3D%5B%5Csqrt%7B%28Clue1_x-FP_x%29%5E2%2B%28Clue1_y-FP_y%29%5E2%7D%2B%5Csqrt%7B%28Clue2_x-Clue1_x%29%5E2%2B%28Clue2_y-Clue1_y%29%5E2%7D%2B%5Csqrt%7B%28Clue3_x-Clue2_x%29%5E2%2B%28Clue3_y-Clue2_y%29%5E2%7D%5D%2A%2Adistance%5C%20per%5C%20unit%5C%5C)
Substituting the values
![d_{T}=[\sqrt{(0-0)^2+(5-0)^2}+\sqrt{(6-0)^2+(0-5)^2}+\sqrt{(0-6)^2+(-5-0)^2}]*50 \text{ feet}\\d_{T}=[\sqrt{(0)^2+(5)^2}+\sqrt{(6)^2+(-5)^2}+\sqrt{(-6)^2+(-5)^2}]*50 \text{ feet}\\d_{T}=[\sqrt{0+25}+\sqrt{36+25}+\sqrt{36+25}]*50 \text{ feet}\\d_{T}=[\sqrt{25}+\sqrt{61}+\sqrt{61}]*50 \text{ feet}\\d_{T}=[5+7.81+7.81]*50 \text{ feet}\\d_{T}=[20.62]*50 \text{ feet}\\d_{T}=1031 \text{ feet}\\](https://tex.z-dn.net/?f=d_%7BT%7D%3D%5B%5Csqrt%7B%280-0%29%5E2%2B%285-0%29%5E2%7D%2B%5Csqrt%7B%286-0%29%5E2%2B%280-5%29%5E2%7D%2B%5Csqrt%7B%280-6%29%5E2%2B%28-5-0%29%5E2%7D%5D%2A50%20%5Ctext%7B%20feet%7D%5C%5Cd_%7BT%7D%3D%5B%5Csqrt%7B%280%29%5E2%2B%285%29%5E2%7D%2B%5Csqrt%7B%286%29%5E2%2B%28-5%29%5E2%7D%2B%5Csqrt%7B%28-6%29%5E2%2B%28-5%29%5E2%7D%5D%2A50%20%5Ctext%7B%20feet%7D%5C%5Cd_%7BT%7D%3D%5B%5Csqrt%7B0%2B25%7D%2B%5Csqrt%7B36%2B25%7D%2B%5Csqrt%7B36%2B25%7D%5D%2A50%20%5Ctext%7B%20feet%7D%5C%5Cd_%7BT%7D%3D%5B%5Csqrt%7B25%7D%2B%5Csqrt%7B61%7D%2B%5Csqrt%7B61%7D%5D%2A50%20%5Ctext%7B%20feet%7D%5C%5Cd_%7BT%7D%3D%5B5%2B7.81%2B7.81%5D%2A50%20%5Ctext%7B%20feet%7D%5C%5Cd_%7BT%7D%3D%5B20.62%5D%2A50%20%5Ctext%7B%20feet%7D%5C%5Cd_%7BT%7D%3D1031%20%5Ctext%7B%20feet%7D%5C%5C)
So the total distance travelled is 1031 feet.
The grade of the path in the mountain is calculated by determining first the ratio between the rise over the run and multiplying the ratio by 100%.
For Path A:
grade = (rise / run) x 100%
grade = (1414/ 3535) x 100% = 40%
<em>Answer: 40%</em>
For Path B:
grade = (rise / run) x 100%
grade = (4.26 m/ 22 m) x 100% = 19.36%
Answer: 19.36%
What's the question!???????
