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lesya [120]
3 years ago
5

The dimensions of an office conference room are 15 feet by 27 feet. if the conference room blueprint dimensions are 5 centimeter

s by 9 centimeters, what is the scale of the blueprint?
Mathematics
2 answers:
Tasya [4]3 years ago
8 0
The scale of the blueprint is 1cm= 3ft
marysya [2.9K]3 years ago
6 0

Answer:

1cm=4feet

on study island

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[PICTURE ATTACHED] HEELPP!
liraira [26]

Answer:

saving money

Step-by-step explanation:

it wouldn't be none with repaid yet!

8 0
2 years ago
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Lim (n/3n-1)^(n-1)<br> n<br> →<br> ∞
n200080 [17]

Looks like the given limit is

\displaystyle \lim_{n\to\infty} \left(\frac n{3n-1}\right)^{n-1}

With some simple algebra, we can rewrite

\dfrac n{3n-1} = \dfrac13 \cdot \dfrac n{n-9} = \dfrac13 \cdot \dfrac{(n-9)+9}{n-9} = \dfrac13 \cdot \left(1 + \dfrac9{n-9}\right)

then distribute the limit over the product,

\displaystyle \lim_{n\to\infty} \left(\frac n{3n-1}\right)^{n-1} = \lim_{n\to\infty}\left(\dfrac13\right)^{n-1} \cdot \lim_{n\to\infty}\left(1+\dfrac9{n-9}\right)^{n-1}

The first limit is 0, since 1/3ⁿ is a positive, decreasing sequence. But before claiming the overall limit is also 0, we need to show that the second limit is also finite.

For the second limit, recall the definition of the constant, <em>e</em> :

\displaystyle e = \lim_{n\to\infty} \left(1+\frac1n\right)^n

To make our limit resemble this one more closely, make a substitution; replace 9/(<em>n</em> - 9) with 1/<em>m</em>, so that

\dfrac{9}{n-9} = \dfrac1m \implies 9m = n-9 \implies 9m+8 = n-1

From the relation 9<em>m</em> = <em>n</em> - 9, we see that <em>m</em> also approaches infinity as <em>n</em> approaches infinity. So, the second limit is rewritten as

\displaystyle\lim_{n\to\infty}\left(1+\dfrac9{n-9}\right)^{n-1} = \lim_{m\to\infty}\left(1+\dfrac1m\right)^{9m+8}

Now we apply some more properties of multiplication and limits:

\displaystyle \lim_{m\to\infty}\left(1+\dfrac1m\right)^{9m+8} = \lim_{m\to\infty}\left(1+\dfrac1m\right)^{9m} \cdot \lim_{m\to\infty}\left(1+\dfrac1m\right)^8 \\\\ = \lim_{m\to\infty}\left(\left(1+\dfrac1m\right)^m\right)^9 \cdot \left(\lim_{m\to\infty}\left(1+\dfrac1m\right)\right)^8 \\\\ = \left(\lim_{m\to\infty}\left(1+\dfrac1m\right)^m\right)^9 \cdot \left(\lim_{m\to\infty}\left(1+\dfrac1m\right)\right)^8 \\\\ = e^9 \cdot 1^8 = e^9

So, the overall limit is indeed 0:

\displaystyle \lim_{n\to\infty} \left(\frac n{3n-1}\right)^{n-1} = \underbrace{\lim_{n\to\infty}\left(\dfrac13\right)^{n-1}}_0 \cdot \underbrace{\lim_{n\to\infty}\left(1+\dfrac9{n-9}\right)^{n-1}}_{e^9} = \boxed{0}

7 0
3 years ago
Angelo earns $2,080 each month. His total deductions are 30% of his pay. How much is deducted from his pay each month? 
Fofino [41]
C. $693.33. Just round. It helps. Round 2,080 to 2,100. Then whats 30% of 2,100? It's easy just think of 21 divided by 3, which equals 7. So, 700 and the closest answers to that is $693.33. That's just the easy way instead of doing the math out. And it is also common sense that B or D wouldn't be it. So your left with C or A. :)
7 0
3 years ago
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Aubree invests money in an account paying simple interest. She invests $30 and no
Marianna [84]

Answer:

8%

Step-by-step explanation:

$30 divided by 100= 0.3/1%

0.3x8=$2.40

$30+$2.4=32.40

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2 years ago
Is 3^2 + 3^3 equal to 3^5?Explain.
Whitepunk [10]

Answer:

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Step-by-step explanation:

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3 years ago
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