Answer:
NH3 , SO3 , BF3
Explanation:
trigonal planar = AB3 ------------> Coordination number = 3
for example = NH3 , SO3 , BF3
all of them are trigonal planar
Answer:
See explanation below.
Explanation:
We can obtain the Gibb's free energy from the formula;
∆G= ∆H - T∆S
Where;
∆G = change in free energy= the unknown
∆H= change in enthalpy = 3352 kJ
∆S= change in entropy of the solution= 625.1 J/K
T= absolute temperature = 298 K
Substituting values;
∆G= 3352 ×10^3 J - (298 K × 625.1 J/K)
∆G= 3352 ×10^3 J - 186279.8
∆G= 3.16 × 10^6 J
At 5975K,
∆G= ∆H - T∆S
∆G= 3352 ×10^3 J - (5975K × 625.1 J/K)
∆G= 3.352 ×10^6 J - 3.735 × 10^6
∆G= -3.83×10^5 J
At equilibrium, ∆G=0, Teq is given by;
0= 3352 ×10^3 J - (Teq × 625.1 J/K)
0= 3352 ×10^3 - 625.1Teq
625.1Teq = 3352 ×10^3
Teq= 3352 ×10^3/625.1
Teq= 5362.3 K
Answer:
C1 * V1 = C2 * V2
Explanation:
Where ‘C’ and ‘V’ refer to concentration and volume, ‘1’ and ‘2’ to solution 1 and 2 respectively. So, if ‘1’ refers to the HCl solution, we want to solve this equation for C1.
V1 = (C2*V2)/C1 = (0.4 * 50)/40 = 0.5 M
Most of these look like dilution questions which follow a general pattern;
<span>Use M1V1 = M2V2 (because moles in a solution stays constant if diluted) </span>
<span>so, the Concentration before * Volume before = Concentration after * Volume after </span>
<span>Using the first question as an example; 0.2*50 = 100 * M2 </span>
<span>Rearranging for M2: 0.1 </span>
<span>Therefore the concentration of the final solution is 0.1 M </span>
<span>we know that to work out pH you must use negative logs to base 10; i.e. -log(0.1) gives you the pH for this solution which is 1</span>