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Marysya12 [62]
4 years ago
9

Which methods would be suitable for determining the concentration of an aqueous solution of KMnO4? I. Visible spectrophotometry

(colorimetry) II. Redox titration (A) I only (C) Both I and II (B) II only (D) Neither I nor II
Chemistry
1 answer:
Elodia [21]4 years ago
3 0

Answer:

C

Explanation:

Since the solution have an observable color, that means that it absorbs light in the visible region hence it can be determined by colorimetry. Secondly, KMnO4 is a reducing agent which can be titrated against an oxidizing agent and it's concentration accurately determined.

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What is Keg for the reaction N2 + 3H2 = 2NH2 if the equilibrium
AlladinOne [14]

<u>Answer:</u> The equilibrium constant for the given reaction is 1.33

<u>Explanation:</u>

We are given:

Equilibrium concentration of ammonia = 2 M

Equilibrium concentration of nitrogen gas = 3 M

Equilibrium concentration of hydrogen gas = 1 M

For the given chemical equation:

N_2+3H_2\rightleftharpoons 2NH_3

The expression of K_{eq} for above equation follows:

K_{eq}=\frac{[NH_3]^2}{[N_2][H_3]^3}

Putting values in above equation, we get:

K_{eq}=\frac{(2)^2}{3\times (1)^3}\\\\K_{eq}=1.33

Hence, the equilibrium constant for the given reaction is 1.33

4 0
3 years ago
If a boulder sits at rest on top of a mountain what conclusion can be made about the forces acting on the
maks197457 [2]

A boulder sits at rest on top of a mountain. What conclusion can be made about the forces acting on the boulder? The forces acting on the boulder are balanced (net force equals zero).

6 0
3 years ago
Read 2 more answers
How many grams of H2 would be formed if 34 grams of carbon reacted with an unlimited amount of H2O? The reaction is:
Readme [11.4K]

Answer:

There is 5.72 grams of H2 formed

1)  C+ H2O → CO + H2

2) We start with 34 grams of carbon that will react with an excess of H2O

3) 5.72 grams of H2

Explanation:

Step 1: Data given

Mass of carbon = 34.00 grams

H2O is in excess

Molar mass of C = 12 g/mol

Molar mass of H2O = 18.02 g/mol

Step 2: The balanced equation

C+ H2O → CO + H2

Step 3: What is the starting substance

We start with 34 grams of carbon that will react with an excess of H2O

Step 4: Calculate moles carbon

Moles C = mass C / molar mass C

Moles C = 34.00 grams / 12.00 g/mol

Moles C = 2.833 moles

Step 5: Calculate moles H2

Carbon is the limiting reactant.

For 1 mol Carbon we need 1 mol H20 to produce 1 mol CO and 1 mol H2

For 2.833 moles C we'll have 2.833 moles H2

Step 6: Calculate mass of H2

Mass H2 = moles H2 * molar mass H2

Mass H2 = 2.833 moles * 2.02 g/mol

Mass H2 = 5.72 grams of H2

8 0
4 years ago
Just need help on this one
lys-0071 [83]

Answer:

2Cs+Sr(CrO4)-->Cs2(CrO4)+Sr

Explanation:

just set them equal, only value that changed was the amount of cesium(Cs)

7 0
3 years ago
Read 2 more answers
Write a balanced half-reaction for the reduction of dichromate ion to chromium ion in acidic aqueous solution. Be sure to add ph
Serhud [2]

Answer:

The balanced half-reaction for the reduction of dichromate ion to chromium ion in acidic aqueous solution:

Cr_2O_7^{2-}(aq)+14H^+(aq)+6e^-\rightarrow 2Cr^{3+}(aq)+7H_2O(l)

Explanation:

The reaction :

Cr_2O_7^{2-}\rightarrow Cr^{3+}

Balancing of reaction in an acidic medium:

Step 1: Balance the atoms in the reaction:

Cr_2O_7^{2-}(aq)\rightarrow 2Cr^{3+}(aq)

Step 2: Balance oxygen atom by adding water on the side where no oxygen or less oxygen atom is present;

Cr_2O_7^{2-}(aq)\rightarrow 2Cr^{3+}(aq)+7H_2O(l)

Step 3: Balance the hydrogen atom by adding  hydrogen ions on the side where water is absent:

Cr_2O_7^{2-}(aq)+14H^+(aq)\rightarrow 2Cr^{3+}(aq)+7H_2O(l)

Step 4: Now balance charge by adding electrons on the side where more positive charge is present

Cr_2O_7^{2-}(aq)+14H^+(aq)+6e^-\rightarrow 2Cr^{3+}(aq)+7H_2O(l)

The balanced half-reaction for the reduction of dichromate ion to chromium ion in acidic aqueous solution:

Cr_2O_7^{2-}(aq)+14H^+(aq)+6e^-\rightarrow 2Cr^{3+}(aq)+7H_2O(l)

6 0
3 years ago
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