Question

Carlos is making phosphorus trichloride using the equation below. He uses 15.5 g of phosphorus and collects 50.9 g of phosphorus chloride.
2P +3Cl2 → 2PCl3


How much chlorine reacted with the phosphorus?

Answer 1

Answer:

Answer: 35.4 g

C is the answer

Explanation:

Answer 2

Answer : The mass of chlorine reacted with the phosphorus is, 53.25 grams.

Explanation :

First we have to calculate the moles of phosphorus.

$\text{Moles of phosphorus}=\frac{\text{Mass of phosphorus}}{\text{Molar mass of phosphorus}}$

$\text{Moles of phosphorus}=\frac{15.5g}{31g/mol}=0.5mol$

Now we have to calculate the moles of $Cl_2$

The balanced chemical reaction is:

$2P+3Cl_2\rightarrow 2PCl_3$

From the balanced chemical reaction, we conclude that

As, 2 moles of phosphorous react with 3 moles of $Cl_2$

So, 0.5 moles of phosphorous react with $\frac{3}{2}\times 0.5=0.75$ moles of $Cl_2$

Now we have to calculate the mass of $Cl_2$

$\text{Mass of }Cl_2=\text{Moles of }Cl_2\times \text{Molar mass of }Cl_2$

Molar mass of $Cl_2$ = 71 g/mol

$\text{Mass of }Cl_2=0.75mol\times 71g/mol=53.25g$

Therefore, the mass of chlorine reacted with the phosphorus is, 53.25 grams.