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mezya [45]
3 years ago
14

Apples are sold in bags of four that cost $5, or bags of six that costs $7 per bag. What is the smallest cost at which you can b

uy 74 apples?
Mathematics
1 answer:
babunello [35]3 years ago
3 0
STEP 1:
BAGS OF FOUR
find number of bags needed to total 74 apples

= 74 ÷ 4 apples/bag
= 18.5 bags

*must round up to 19 bags because we cannot buy a partial bag

STEP 2:
BAGS OF FOUR
calculate price of 19 bags of 4 apples per bag

= 19 bags * $5/bag
= $95 for 19 bags of 4 apples/bag

STEP 3:
BAGS OF SIX
find number of bags needed to total 74 apples

= 74 ÷ 6 apples per bag
= 12.3333 bags needed

*must round up to 13 bags because we cannot buy a partial bag

STEP 4:
BAGS OF SIX

calculate price of 13 bags of 6 apples per bag

= 13 bags * $7 per bag
= $91 for 13 bags of 6 apples/bag


ANSWER: The smallest cost to buy 74 apples is $91.

Hope this helps! :)
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A farmer has a field in the shape of a triangle. The farmer has asked the manufacturing class at your school to build a metal fe
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Answer:

<em>Fencing required = 1586 m</em>

Step-by-step explanation:

The given statements can be thought of a triangle \triangle ABC as shown in the diagram attached.

A be the 1st vertex, B be the 2nd vertex and C be the 3rd vertex.

Distance between 1st and 2nd vertex, AB = 435 m

Distance between 2nd and 3rd vertex, AC = 656 m

\angle A =49^\circ

To find:

Fencing required for the triangular field.

Solution:

Here, we know two sides of a triangle and the angle between them.

To find the fencing or perimeter of the triangle, we need the third side.

Let us use <em>Cosine Rule </em>to find the third side.

Formula for cosine rule:

cos A = \dfrac{b^{2}+c^{2}-a^{2}}{2bc}

Where  

a is the side opposite to \angle A

b is the side opposite to \angle B

c is the side opposite to \angle C

\Rightarrow cos 49^\circ = \dfrac{656^{2}+435^{2}-BC^{2}}{2\times 435\times 656}\\\Rightarrow BC^2 = 430336+189225-2 (435)(656)cos49^\circ\\\Rightarrow BC^2 = 430336+189225-570720\times cos49^\circ\\\Rightarrow BC^2 =619561-570720\times cos49^\circ\\\Rightarrow BC \approx 495\ m

Perimeter of the triangle = Sum of three sides = AB + BC + AC

Perimeter of the triangle = 435 + 495 + 656 = <em>1586 m</em>

<em></em>

<em>Fencing required = 1586 m</em>

4 0
3 years ago
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Answer:

The answer to this question is x=3

Step-by-step explanation:

If you create the graph and then plot the points you will get a depiction of the trapazoids. using this you will find that they have reflected over the x=3 line.

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The length of a rectangle is 5 times the width. If the perimeter is to be greater than 36 meters. What are the possible values f
Lostsunrise [7]

Answer:

  The width must be greater than 3 meters.

Step-by-step explanation:

Let w represent the width. Then 5w will represent the length, which is 5 times the width. The perimeter is the total of the side lengths of the rectangle, so is ...

  P = 2w + 2(5w) = 12w

We want this to be greater than 36 m, so ...

  P > 36 m

  12w > 36 m . . . . . . . substitute our expression for P

  w > 3 m . . . . . . . . . . divide by 12

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