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Dmitry [639]
3 years ago
13

For what reason would we use the distance formula to determine the type of quadrilateral?

Mathematics
1 answer:
Whitepunk [10]3 years ago
6 0

Answer:

Sides/diagonals are congruent

Step-by-step explanation:

If the distance formula is used to determine the type of quadrilateral, then we are interested in knowing whether the opposite sides are congruent or adjacent sides are congruent.

We can also use the length of diagonals to determine which type of quadrilateral.

For instance the square has all sides equal.

The diagonals of the rectangle are congruent.

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Naddika [18.5K]
$11.81.
$40 - 3(4x15) - 8.99 - 3(2.25) = $11.81
3 0
3 years ago
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Formulate the quadratic function that contains the points (-1,4), (0,2) and (2,4).
larisa86 [58]

f(x) = x2 - x + 2

f(-1)=(-1)²-(-1)+2=4   contain the point (-1,4)

f(0) = 0²-0+2 = 2   contain  the point (0,2)

f(2) = 2²-2+2 =4   contain the point (2,4)

4 0
2 years ago
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Find the missing angle
Mila [183]

Answer:

55 degrees

Step-by-step explanation:

All angles in a triangle must equal 180 degrees when added together

They provide you with 2 angles 35 degrees and 90 degrees

So, you add 35 + 90 = 125

So you know that the 2 angles they give you equal 125 degrees

Now, you subtract 180 - 125 = 55

So the missing angle is 55 degrees

8 0
3 years ago
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Conditional Probability Assistance?
krek1111 [17]

Let the event A=\{ Sophomore \}, B=\{ Boy \}

The the probability of the events

P(A \cap B)=\frac{5}{12+18} =\frac{1}{6}

P( B)=\frac{12}{12+18} =\frac{2}{5}

The conditional probability

P(Sophomore|Boy)=P(A|B)=\frac{P(A \cap B)}{P(B)} =\frac{1/6}{2/5} =\frac{5}{12}

5 0
3 years ago
Please Help I Don't Undertand.
frozen [14]

If triangles AMN and ABC are similar, then

AM/AB = AN/AC

or

AM/(AM + MB) = AN/(AN + NC)

Check if this is true:

AM/AB = 21/(21 + 9) = 21/30 = 7/10

AN/AC = 14/(14 + 6) = 14/20 = 7/10

The angle at vertex A is common to both of the triangles.

Then by the side-angle-side (SAS) similarity theorem, the triangles are indeed similar.

4 0
1 year ago
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