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2 years ago

Please Help I Don't Undertand.

Mathematics

1 answer:

frozen [14]2 years ago

4 0

If triangles AMN and ABC are similar, then

AM/AB = AN/AC

AM/(AM + MB) = AN/(AN + NC)

Check if this is true:

AM/AB = 21/(21 + 9) = 21/30 = 7/10

AN/AC = 14/(14 + 6) = 14/20 = 7/10

The angle at vertex A is common to both of the triangles.

Then by the side-angle-side (SAS) similarity theorem, the triangles are indeed similar.

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You decide to put $150 in a savings account to save for a $3,000 down payment on a new car. If the account has an interest rate

zheka24 [161]

The formula is
A=p (1+r/k)^kt
A future value 3000
P present value 150
R interest rate 0.025
T time?
3000=150 (1+0.025/12)^12t
Solve for t
3000/150=(1+0.025/12)^12t
Take the log
Log (3000/150)=log (1+0.025/12)×12t
12t=Log (3000/150)÷log (1+0.025/12)
T=(log(3,000÷150)÷log(1+0.025÷12))÷12
T=119.95 years

8 0

3 years ago

Read 2 more answers

Jack is purchasing a stock that pays an annual dividend of $3.42 per share. If he purchases 400 shares for $53.18 per share, wha

sergij07 [2.7K]

Answer:

1368 dollars.

Step-by-step explanation:

given that Jack s purchasing a stock that pays an annual dividend of $3.42 per share

No of shares Jack purchased = 400

Price per share = 53.18$

Amount invested by Jack in shares = $400*53.18 =21272$ dollars

Annual dividend = 3.42 per share

Total dividend = $400*3.42 = 1368$

Annual income from dividends = 1368 $

7 0

4 years ago

Find all solutions to the equation 2sin(theta)-sqrt (2)=0

Anon25 [30]

Sin(theta)=√2/2
theta is 45, 135

8 0

4 years ago

Find the area that the curve encloses and then sketch it.<br> r = 3 + 8 sin(6)

Rudiy27

Answer:

$A=41\pi\: \text{units}^2\approxA\approx128.8053\:\text{units}^2$

Step-by-step explanation:

I assume you mean $r=3+8\sin\theta$ :

Use the formula $\displaystyle A=\int\limits^a_b \frac{1}{2} {r(\theta)^2} \, d\theta$ where $a$ and $b$ are the lower and upper bounds and $r(\theta)$ is the equation of the polar curve.

Since the graph is symmetrical about the line $\displaystyle \theta=\frac{\pi}{2}$ , let the bounds of integration be $\displaystyle \biggr(-\frac{\pi}{2},\frac{\pi}{2}\biggr)$ to find half the area of the curve, and then find twice of that area:

$\displaystyle A=\int\limits^a_b \frac{1}{2} {r(\theta)^2} \, d\theta\\\\A=2\int\limits^{\frac{\pi}{2}}_{-\frac{\pi}{2}} \frac{1}{2} {(3+8\sin\theta)^2} \, d\theta\\\\A=\int\limits^{\frac{\pi}{2}}_{-\frac{\pi}{2}} 9+48\sin\theta+64\sin^2\theta \, d\theta\\\\A=\int\limits^{\frac{\pi}{2}}_{-\frac{\pi}{2}} 9+48\sin\theta+64\biggr(\frac{1-\cos2\theta}{2} \biggr) \, d\theta\\\\\\A=\int\limits^{\frac{\pi}{2}}_{-\frac{\pi}{2}} (9+48\sin\theta+32-32\cos2\theta) \, d\theta$

$\displaystyle A=\int\limits^{\frac{\pi}{2}}_{-\frac{\pi}{2}} (41+48\sin\theta-32\cos2\theta) \, d\theta\\\\A=41\theta-48\cos\theta-16\sin2\theta\biggr|^{\frac{\pi}{2}}_{-\frac{\pi}{2}}\\\\$

$A=\biggr[41\biggr(\frac{\pi}{2}\biggr)-48\cos\biggr(\frac{\pi}{2}\biggr)-16\sin2\biggr(\frac{\pi}{2}\biggr)\biggr]-\biggr[41\biggr(-\frac{\pi}{2}\biggr)-48\cos\biggr(-\frac{\pi}{2}\biggr)-16\sin2\biggr(-\frac{\pi}{2}\biggr)\biggr]\\\\A=\biggr[\frac{41\pi}{2}-24\sqrt{2}\biggr]-\biggr[-\frac{41\pi}{2}+24\sqrt{2}\biggr]\\ \\A=41\pi\\\\A\approx128.8053$

Thus, the area of the curve is 41π square units. See below for a graph of the curve and its shaded area.

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3 years ago

2 triflies cost £7<br> how much would 6 cost

Nikolay [14]

Answer 21

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers