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sesenic [268]
3 years ago
10

The area of the paralleogram is 184 units squared

Mathematics
2 answers:
goldenfox [79]3 years ago
5 0
What do you mean by this The area of the paralleogram is 184 units squaredgive me your full question then i can help you

podryga [215]3 years ago
4 0
Give the full answer do you mean if it's right or
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Mr. Ahmed has 9 water heaters for his apartment buildings. each heater weighs 32 kilograms. How many grams do all 9 water heater
iris [78.8K]
Multiply 32X 9 = 288kg

they asked you to convert the kilograms to grams so divide the 288kg by a 1000= 0.288grams 

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3 years ago
What is the measure of <br> a) 264°<br> b) 132°<br> c) 71°<br> d) 66°
Yuki888 [10]

The answer is 132° because there angle CDE is 87° so you know it's more of that. And, 264° is way too wide.

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3 years ago
If √7-y=6, then y= <br> -29<br> -5<br> 1<br> 29<br> I don't know
sleet_krkn [62]

Hello!

√7 - y = 6 <=>

<=> -y = 6 - √7 <=>

<=> y = -6 + √7 => √7 - (-6 + √7) = 6

Good luck! :)

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2 years ago
Pls show full working out
sweet-ann [11.9K]

Answer:

  • Question 1a. i) x=1.8m

  • Question 1a. ii)   Volume=27.6m^3

  • Question 1b) Volume=65.9m^3

Explanation:

<u><em>Question 1 a. i) Find the value of x.</em></u>

         tan(\theta )=\dfrac{opposite\text{ }leg}{adjacent\text{ }leg}

For the smalll triangle you can write:

        tan(\theta )=\dfrac{x}{1m}

For tthe big triangle:

      tan(\theta )=\dfrac{x+2.7m}{2.5m}

Substitute:

        \dfrac{x}{1m}=\dfrac{x+2.7m}{2.5m}

Solve for x:

        2.5x=x+2.7m\\\\2.5x-x=2.7m\\\\1.5x=2.7m\\\\x=2.7m/1.5\\\\x=1.8m

<u><em>Question 1a ii) Find the volume of the frustrum</em></u>

  • Find the volume of a cone with height = 2.7m + 1.8m = 4.5m, and radius = 2.5m

Formula:

         Volume=(1/3)\pi \times radius^2\times height

Substitute:

         Volume=(1/3)\pi \times (2.5m)^2\times 4.5m=9.375\pi m^3

  • Find the volume of a cone with heigth = 1.8m and radius = 1m

        Volume=(1/3)\pi \times (1m)^2\times 1.8m=0.6\pi m^3

  • Subtract the volume of the small cone from the volume of the big cone

        Volume\text{ }of\text{ }frustrum=9.375\pi m^3-0.6\pi m^3=8.775\pi m^3\approx 27.6m^3

<u><em>Question 1b. Calculate the volume of the bin</em></u>

<u>i) Upper frustrum</u>

This is the same frustrum from the equation of above, thus ist volume is 27.6m³.

<u>ii) Lower frustrum</u>

            \dfrac{x}{2.0m}=\dfrac{x+2.4m}{2.5m}

           2.5x=2(x+2.4m)\\\\2.5x=2x+4.8m\\\\0.5x=4.8m\\\\x=9.6m

        Volume=(1/3)\pi \times (2.5m)^2\times (9.6m+2.4m)-(2.0m)^2\times (9.6m)

       Volume=38.3m^3

<u>iii) Add the volume of the two frustrums</u>

  • Volume=27.6m^3+38.3m^3=65.9m^3

6 0
3 years ago
Snow fell at a rate of ¾ of an inch/hour. How much snow fell in a period of 6 hours?
Sveta_85 [38]

Answer:

4.5

Step-by-step explanation:

4 0
2 years ago
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