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3 years ago

Please help! Will be marking brainliest!

Mathematics

1 answer:

Ludmilka [50]3 years ago

5 0

Answer:

integer and rational

Step-by-step explanation:

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The graph of f(t) = 6 x 2^t shows the value of a rare coin in year t. What is the meaning of the y-intercept?

Flauer [41]

When the graph intersects the y-axis, it means it's x-coordinate is 0, or t = 0.
Hence, f(t) = 6 × 2^0 = 6.
y = 6 at y-intercept.

3 0

2 years ago

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NO LINKS!!!!

DedPeter [7]

9514 1404 393

Answer:

3. vertical stretch by a factor of 2; shift right 1 and down 1

4. shift left 4 and up 4 (no stretch or shrink)

Step-by-step explanation:

The vertex form equation is ...

y = a(x -h)^2 +k

It represents a vertical stretch of the parent function by a factor of 'a', a right shift of 'h', and an upward shift of 'k'.

Compare the the given equations to the above form to see the transformations.

3. (a, h, k) = (2, 1, -1) ⇒ vertical stretch by a factor of 2; shift right 1, down 1

4. (a, h, k) = (1, -4, 4) ⇒ no vertical stretch; shift left 4, up 4

6 0

3 years ago

HELP DUE IN 10 MINUTES!

vfiekz [6]

Answer:

Step-by-step explanation:

97.65 is roughly 100

68℅ of 100 is 68

so it's 68

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3 years ago

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Quart cartons of milk should contain at least 32 ounces. A sample of 22 cartons was taken and amount of milk in ounces was recor

victus00 [196]

Answer:

32 oz

Step-by-step explanation:

5 0

3 years ago

WILL GIVE BRAINLIEST

stira [4]

The air force plane travelled for a total of 6.9 hours.

<u>SOLUTION: </u>

Given, An Air Force plane left Nairobi and flew west at an average speed of 159 mph. A cargo plane left sometime later flying in the same direction at an average speed of 207 mph. After flying for 5.3 hours the cargo plane caught up with the Air Force plane.

We have to find the number of hours the Air Force plane flew before the cargo plane caught up.

Now, we know that, $\text { distance travelled }=\text { speed } \times \text { time }$

For air force plane $\rightarrow \text { distance travelled }=159 \mathrm{x} \text { time taken by air force plane }$

$\text { For cargo plane } \rightarrow \text { distance travelled }=207 \times 5.3 \text { hours }$

Now, when cargo plane caught the air force plane the distance travelled by the planes will be equal.

So, $159 \times \text { time taken by air force plane }=207 \times 5.3$

$\Rightarrow =\frac{207 \times 5.3}{159}$

$\Rightarrow =\frac{1097.1}{159}$

Time taken by air force plane = 6.9 hrs

6 0

3 years ago