Question

The average January surface water temperatures (°C) of Lake Michigan from 2000 to 2009 were 5.07, 3.57, 5.32, 3.19, 3.49, 4.25, 4.76, 5.19, 3.94, and 4.34. The data set has the following statistics: x = 4.312 2 = 0.577 What is the standard deviation? Round to the nearest thousandth. 0.333 0.760 2.077 18.593

Answer 1

0.760 I just did this question and this was the answer lol.

Answer 2

Answer:

$\text{Standard Deviation}=0.76$

Step-by-step explanation:

The average January surface water temperatures in °C of Lake Michigan from 2000 to 2009 are,

$5.07, 3.57, 5.32, 3.19, 3.49, 4.25, 4.76, 5.19, 3.94,4.34$

The mean $(\overline{x})$ and variance $(\sigma^2)$ are,

$\overline{x}=\sum_{i=1}^{10}a_i=4.312$

$\sigma^2=\sum _{i=1}^n\dfrac{\left(x_i-\bar{x}\right)^2}{n-1}=0.577$

Standard deviation is the square root of variance.

i.e $\text{Standard Deviation}=\sigma=\sqrt{\sigma ^2}$

$\text{Standard Deviation}=\sqrt{0.577}=0.76$