Initial velocity of the plane is Vo = 0.
acceleration a = 1.3 m/s2
total distance = 2.5 km = 2500m
time taken to reach 2.5 km with 1.3m/s^2 acceleration = t
S = Vo t + 0.5 a t^2
2500 = 0 + (0.5*1.3* t^2)
t^2 = 3846.15
t = 62 s
the maximum velocity plan can reach within 62 s is Vt
Vt = Vo + a t
Vt = 0 + (1.3*62)
Vt = 80.6 m/s
Since 80.6 m/s is greater than 75 m/s, plane can use this runway to takeoff with required speed.
Hey there!
speed=distance/time.
s-speed
s=12/3
s=4
The speed of the car is 4 mph
Hope this helps:) Let me know if you have any questions.
Answer: $106.8
Step-by-step explanation:
Given that the bond price is $100.75
With a 6% brokerage fee
Find the total cost to the nearest cent
First, we calculate the 6% brokerage fee= 6/100 × 100.75
= 0.06 x 100.75
= 6.045
Total cost therefore is the sum of brokerage fee and the cost of bond
= $6.045 + $100.75
= $106.795
To the nearest cent = $106.8
Answer:
3/2
Step-by-step explanation:
Answer:
Third
Step-by-step explanation:
First would be, simplified, 2x+10=2x-10
Second, simplified, -2x-10=2x-10
Third, simplified, -2x-10=-2x-10
Fourth, simplified, -2x+10=2x-10
So it's third :)
hope this helps :D
