Ask question

Ask question

All categories

Vladimir79 [104]

4 years ago

10

the ricky family drove 224 miles for a trip to the beach. at lunch they drove 17 miles to the nearest restaurant and later that

night they drove 36 miles to their hotel. how many miles did they drive that day

1 answer:

goldfiish [28.3K]4 years ago

7 0

Answer:

277 miles

Step-by-step explanation:

224+17+36=277

You might be interested in

PLZ SOMEONE HELP ME WITH THIS!!

Mandarinka [93]

B = 2.98 and c = 5.77

7 0

3 years ago

Find the distance between the points (–3, 2) and (0, 3).

Oksi-84 [34.3K]

Answer: $\sqrt{10}\ units$

Step-by-step explanation:

You need to use the following formula:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Given the points (-3, 2) and (0, 3), you can identify that:

$x_2=-3\\x_1=0\\\\y_2=2\\y_1=3$

Then, the final step is to substitutes these coordinates into the formula.

So, the distance between the given points is:

$d=\sqrt{(-3-0)^2+(2-3)^2}\\\\d=\sqrt{10}\ units$

6 0

3 years ago

If f(x) = 2x2 + 2 and g(x) = x2 - 1, find (f - g)(x)I

erastovalidia [21]

9514 1404 393

Answer:

C. x^2 + 3

Step-by-step explanation:

Substitute for f(x) and g(x) and simplify.

(f -g)(x) = f(x) -g(x)

(f -g)(x) = (2x^2 +2) -(x^2 -1) = 2x^2 +2 -x^2 +1

(f -g)(x) = x^2 +3

4 0

3 years ago

Bella and Heather put some money into their money boxes every week. The amount of money (y), in dollars, in their money boxes af

Hatshy [7]

Answer:

$\boxed{ \text{B. 10 weeks, \$310 }}\\$

Step-by-step explanation:

We have two conditions:

$\begin{array}{lrcll}(1) & y & = & 25x + 60 & \\(2) & y & = & 30x + 10 & \\ & 25x + 60 & = & 30 x + 10 & \text {Set (1) = (2)} \\ & 50 & = & 5x & \text{Subtracted 25x from each side} \\& x & = & 10 &\text{Divided each side by 5} \\\end{array}\\$ $\\\boxed{ \textbf{The number of weeks is }x = 10}\\$

Bella: y = 25x + 60 = 25(10) + 60 = 250 + 60 = 310

Heather: y = 30x + 10 = 30(10) + 10 = 300 + 10 = 310

7 0

3 years ago

For how many real values of x is <img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B120-%5Csqrt%7Bx%7D%7D%20" id="TexFormula1" title

leva [86]

A good place to start is to set $\sqrt{x}$ to y. That would mean we are looking for $\sqrt{120-y}$ to be an integer. Clearly, $y\leq 120$ , because if y were greater the part under the radical would be a negative, making the radical an imaginary number, not an integer. Also note that since $\sqrt{x}$ is a radical, it only outputs values from $[0,\infty]$ , which means y is on the closed interval: $[0,120]$ .

With that, we don't really have to consider y anymore, since we know the interval that $\sqrt{x}$ is on.

Now, we don't even have to find the x values. Note that only 11 perfect squares lie on the interval $[0,120]$ , which means there are at most 11 numbers that x can be which make the radical an integer. All of the perfect squares are easily constructed. We can say that if k is an arbitrary integer between 0 and 11 then:

$\sqrt{120-\sqrt{x}}=k \implies \\ \sqrt{x}=k^2-120 \implies\\ x=(k^2-120)^2$

Which is strictly positive so we know for sure that all 11 numbers on the closed interval will yield a valid x that makes the radical an integer.

5 0

3 years ago