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Murljashka [212]
2 years ago
5

Ruby and her friends are going into a restaurant. How much would it cost to buy 3

Mathematics
1 answer:
Gnoma [55]2 years ago
8 0

Answer:

Step-by-step explanation:

3x2.25=6.75

4x4=16

16+6.75=22.75

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What is the nth term rule of the quadratic sequence below?
Vladimir [108]

Answer:

3n² + 5n - 2

Step-by-step explanation:

<u>Given sequence</u>:

6, 20, 40, 66, 98, 136, ...

Calculate the <u>first differences</u> between the terms:

6 \underset{+14}{\longrightarrow} 20 \underset{+20}{\longrightarrow} 40 \underset{+26}{\longrightarrow} 66 \underset{+32}{\longrightarrow} 98 \underset{+38}{\longrightarrow} 136

As the first differences are not the same, calculate the <u>second differences:</u>

14 \underset{+6}{\longrightarrow} 20 \underset{+6}{\longrightarrow} 26 \underset{+6}{\longrightarrow} 32 \underset{+6}{\longrightarrow} 38

As the <u>second differences are the same</u>, the sequence is quadratic and will contain an n² term.

The <u>coefficient</u> of the n² term is <u>half of the second difference</u>.

Therefore, the n² term is:  3n²

Compare 3n² with the given sequence:

\begin{array}{|c|c|c|c|c|}\cline{1-5} n & 1 & 2 & 3 & 4\\\cline{1-5} 3n^2 & 3 & 12 & 27 & 48 \\\cline{1-5} \sf operation & +3&+8 & +13 & +18 \\\cline{1-5} \sf sequence & 6 & 20 & 40 & 66\\\cline{1-5}\end{array}

The second operations are different, therefore calculate the differences <em>between</em> the second operations:

3 \underset{+5}{\longrightarrow} 8 \underset{+5}{\longrightarrow} 13\underset{+5}{\longrightarrow} 18

As the differences are the same, we need to add 5n as the second operation:

\begin{array}{|c|c|c|c|c|}\cline{1-5} n & 1 & 2 & 3 & 4\\\cline{1-5} 3n^2  +5n & 8&22 & 42 & 68\\\cline{1-5}\sf operation & -2 &-2  &-2  & -2  \\\cline{1-5} \sf sequence & 6 & 20 & 40 & 66\\\cline{1-5}\end{array}

Finally, we can clearly see that the operation to get from 3n² + 5n to the given sequence is to subtract 2.

Therefore, the nth term of the quadratic sequence is:

3n² + 5n - 2

6 0
1 year ago
A car of 1000 kg starts to move from rest and travels a distance of 150 m in 10 second. How much force is needed?​
allsm [11]
  • Initial velocity=u=0m/s
  • Distance=s=150m
  • Time=t=10s
  • Acceleration=a

Using second equation of kinematics

\\ \sf\longmapsto s=ut+\dfrac{1}{2}at^2

\\ \sf\longmapsto 150=0(10)+\dfrac{1}{2}a(10)^2

\\ \sf\longmapsto 150=\dfrac{1}{2}\times 100a

\\ \sf\longmapsto 50a=150

\\ \sf\longmapsto a=\dfrac{150}{50}

\\ \sf\longmapsto a=3m/s^2

  • Mass=m=1000kg
  • Force=F

Using newtons second law

\\ \sf\longmapsto F=ma

\\ \sf\longmapsto F=1000(3)

\\ \sf\longmapsto F=3000N

3 0
2 years ago
Please help fast!!!!
Monica [59]

Answer:

C

Step-by-step explanation:

The exponent is negative so you put the number under 1 with the exponent positive

6 0
2 years ago
Read 2 more answers
codys bikes rents bikes for $18 plus $5 per hour. mofor paid $48 to rent a bike. For how many hours did he rent the bike?
DerKrebs [107]
First of all, to find out the amount paid for hours in total,
$48-$18=$30
to find how many hours,
$30÷$5=6hrs
3 0
3 years ago
Read 2 more answers
14\4139 what is the answer
Masja [62]

Answer:

14 divided by 4139 is 0.0033824595312878

Step-by-step explanation:

7 0
2 years ago
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