Answer:
![2 \sqrt{15}](https://tex.z-dn.net/?f=2%20%5Csqrt%7B15%7D%20)
Step-by-step explanation:
1) rewrite 60 as it's prime factors.
![\sqrt{2 \times 2 \times 3 \times } 5](https://tex.z-dn.net/?f=%20%5Csqrt%7B2%20%5Ctimes%202%20%5Ctimes%203%20%5Ctimes%20%7D%205)
2) group the smae prime factors into pairs.
![\sqrt{(2 \times 2)} \times 3 \times 5](https://tex.z-dn.net/?f=%20%5Csqrt%7B%282%20%5Ctimes%202%29%7D%20%20%5Ctimes%203%20%5Ctimes%205)
3) Rewrite each pair in exponent form.
![\sqrt{ {2}^{2} \times 3 \times 5 }](https://tex.z-dn.net/?f=%20%5Csqrt%7B%20%7B2%7D%5E%7B2%7D%20%5Ctimes%203%20%5Ctimes%205%20%7D%20)
4) use this role:
![\sqrt{ {x}^{2} } = x](https://tex.z-dn.net/?f=%20%5Csqrt%7B%20%7Bx%7D%5E%7B2%7D%20%7D%20%20%3D%20x)
![2 \sqrt{3 \times 5}](https://tex.z-dn.net/?f=2%20%5Csqrt%7B3%20%5Ctimes%205%7D%20)
5) Simplify.
![4 \sqrt{15}](https://tex.z-dn.net/?f=4%20%5Csqrt%7B15%7D%20)
So, therefor, the answer is option 1.
Answer:
6 3/8 inches (6.375 inches)
Step-by-step explanation:
For simplicity we'll assume that both the photo and the poster board are square. To determine the width of the border, subtract 8.5 inches from the poster board width 21.25 inches, obtaining 12.75 inches, and then divide that 12.75 inches by 2: 6.375 inches (6 3/8 inches).
Set the photo 6 3/8 inches from each edge of the poster board.
Answer:
4
Step-by-step explanation:
To find the mean absolute deviation (MAD), first find the mean (or average).
μ = (59 + 71 + 68 + 75 + 67) / 5
μ = 68
Next, subtract the mean from each value and take the absolute value.
|59 − 68| = 9
|71 − 68| = 3
|68 − 68| = 0
|75 − 68| = 7
|67 − 68| = 1
Sum the results and divide by the number of students.
MAD = (9 + 3 + 0 + 7 + 1) / 5
MAD = 4
Answer:
X= -3
Step-by-step explanation:
3x-9=8x+6
3x-8x=6=9
-5x=15
x=-3