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defon
3 years ago
12

Which graph represents the function f(x) = |x| - 4

Mathematics
1 answer:
Advocard [28]3 years ago
7 0

Answer:

the first one

Step-by-step explanation:

go to desmos graphing calculator and put that equation in and it will graph it for you

Hope it helps

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lisabon 2012 [21]
It will be clearly  B.38mm3
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3 years ago
Which of the following graphs best represents f(x) = −2 sin(4x) + 3?
Artist 52 [7]
The graph for f(x) = sin x <span>is a sinusoidal graph.

</span>f(x) = 2 sin 4x
has an amplitude of 2 or the highest point is 2 and a period of
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3 0
3 years ago
Solve the following system of equations:
Vladimir79 [104]

Answer:

<u><em>(-1,1)</em></u>

Step-by-step explanation:

We can solve this by either graphing and finding ther point the lines intersect, or mathematically,  I'll do both.

<u>Graphing:</u>

<u>Mathematically:</u>

−2x + 4y = 6

y = 2x + 3

See the attached graph.  The lines intersect at (-1,1)

--------------------

I'll rearrange the first equation (to make it easier for me):

−2x + 4y = 6

4y = 2x + 6

y = (1/2)x + 1.5

Now lets substitute the second equation into the first so that we can eliminate y:

y = 2x + 3

[(1/2)x + 1.5] = 2x + 3

- (3/2)x = (3/2)

x = -1

If x = -1:

y = 2(-1) + 3

y = 1

The solution is x = -1 and y = 1, or (-1,1)

=================

Both approaches give us (-1,1), the solution to the system of equations.  It is the only point that satisfies both equations.

3 0
2 years ago
Solve the simultaneous equation<br> 4x-y=9 <br> 2x-3y= -23
MrMuchimi

Answer:

x = 5

y = 11

Step-by-step explanation:

y = 4x - 9

2x -3(4x - 9) = -23

2x - 12x + 27 = -23

-10x = -23 -27

-10x = -50

minus cancels out

x = 5

y = 4(5) -9

y = 20 - 9

y = 11

4 0
3 years ago
Solve the inequality 5u≤8u−21 and write the solution in interval notation
PIT_PIT [208]

Answer:

Step-by-step explanation:

5u\leq 8u-21

Subtract 8u from both sides

-3u\leq -21

Divide by -3 on both sides

u\geq 7

Interval notation: [greater/less than or equal to], (greater or equal to)

[7,∞)

3 0
3 years ago
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