the equations y = –3x + 4 and 3y = –9x + 12 have infinitely many solutions. option B is correct.
<h3>What is the linear system?</h3>
It is a system of an equation in which the highest power of the variable is always 1. A one-dimension figure that has no width. It is a combination of infinite points side by side.
Condition for the parallel lines.
L1, ax + bx + c = 0
L2, dx + ey + f = 0
If
then lines have infinitely many solutions.
<h3>Which
system of equations below has infinitely many solutions?</h3>
y = –3x + 4 and 3y = –9x + 12
On comparing we have
a = -3 , b = 1, and c = 4
d = -9 , e = 3, and f = 12
Then their ratio will be

Hence y = –3x + 4 and 3y = –9x + 12 have infinitely many solutions.
Thus the option B is correct.
More about the linear system link is given below.
brainly.com/question/20379472
In 15 hours bob makes 7.5 boxes. how many boxes can he make in one hour?
so 15 hours=7.5 boxes
divide both sides by 15 to get hours
1 hour=7.5/15
answer is 1 hour=0.5 boxes
Answer:
6m + 18 ≥ 42
Step-by-step explanation:
6m + 18 ≥ 42
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The second number in an ordered pair is the y-coordinate and corresponds to a number on the y-axis.
Answer:
The daily rate is $ 29 and the fee for each kilometer driven is $ 0.35.
Step-by-step explanation:
Since to rent a car, a person is charged a daily rate and a fee for each kilometer driven, and when Chena rented a car for 6 days and drove 320 km, the charge was $ 286.00, while when she rented the same car for 10 days and drove 900 km, the charge was $ 605.00, to determine the daily rate and the fee for each kilometer driven the following calculation must be performed:
286 = 6 days and 320 km
320/6 = 53,333 km
286/6 = $ 47,666
Thus, the value of 1 day and 53,333 km is $ 47,666.
605 = 10 days and 900 km
900/10 = 90 km
605/10 = $ 60.5
Thus, the value of 1 day and 90 km is $ 60.5.
90 - 53,333 = 36,666
60.5 - 47.666 = 12.833
12,833 / 36,666 = value per kilometer traveled
0.35 = value per kilometer traveled
(286 - (0.35 x 320)) / 6 = X
(286/112) / 6 = X
174/6 = X
29 = X
(605 - (0.35 x 900)) / 10 = X
(605 - 315) / 10 = X
290/10 = X
29 = X
Therefore, the daily rate is $ 29 and the fee for each kilometer driven is $ 0.35.