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Romashka [77]
3 years ago
6

Given U = {1,2,3,4....} A = {1,3,5,7,9,11,13} B = {3,5,7}C = {1,2,3,4,5} D = {8,10,12}

Mathematics
1 answer:
Elanso [62]3 years ago
6 0

Answer:

will you pay e if i tell you the answer

Step-by-step explanation:

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5 in<br> Area<br> 6 in<br> 7 in<br> 10 in<br> 15 in<br> HELP I NEED TO FIND AREA
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Answer:

84in

Step-by-step explanation:

10 times 5 = 50 (top half)

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Mean of 7.2,8.5,7.0,8.1,6.7
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Answer:

7.5

Step-by-step explanation:

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3 years ago
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An experiment was performed to determine whether the annealing temperature of ductile iron affects its tensile strength. Five sp
Tcecarenko [31]

Answer:

There are significant differences among the mean tensile strengths for different temperatures.

Step-by-step explanation:

A one-way ANOVA is used to test whether there is significant difference between the means for more than two groups.

The hypothesis can be defined as follows:

<em>H₀</em>: There is no difference between the means, i.e. \mu_{1}=\mu_{2}=\mu_{3}=\mu_{4}.

<em>Hₐ</em>: There is a significant difference between the means, i.e.at least one of the mean is different.

Use MS-Excel to perform the analysis of variance.

Go to Data → Data Analysis → Anova: Single Factor.

A dialog box will open.

Enter the data and enter Alpha as 0.05.

Press OK.

The output is attached below.

The F-value is, 8.40458.

The <em>p</em>-value of the test is, 0.00139.

Decision Rule:

If the p-value of the test is less than the significance level then the null hypothesis will be rejected.

<em>p</em>-value = 0.00139 < <em>α</em> = 0.05

The null hypothesis will be rejected at 5% level of significance.

Concluding that there are differences among the mean tensile strengths for different temperatures.

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