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MArishka [77]
3 years ago
14

5+666+546+5365+32256=?

Mathematics
2 answers:
yaroslaw [1]3 years ago
6 0

Answer:38838


Step-by-step explanation:

line them up one set of numbers under the other, answer add them together. or use a calculator lol

lora16 [44]3 years ago
5 0

Answer:38838


Step-by-step explanation:


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Barbara deposited $300 in the bank. If the bank pays her simple interest at the rate of 4 percent per year, how much money will
grigory [225]

Answer:

309

Step-by-step explanation:

The formula for simple interest is

A = P(1 + rt)

where A is the amount of money in the account

P is the principal invested

r is the interest rate in decimal form

t is the time invested in years

We know

P = 300

r = 4% = .04

t = 9 months = 9 months * 1 year/12 months = .75 year

Substituting into the equation

A = 300(1 + .04*.75)

  =300 (1+.03)

  =300(1.03)

   = 309

4 0
3 years ago
1. Using the formula for the probability of one event or another event, calculate the probability of drawing a card from a stand
ddd [48]
A standard deck has 52 cards.
A standard deck has 4 jacks.
A standard deck has 13 clubs.

From this, we can derive the following:
The probability of drawing a jack is 4/52 or 1/13
The probability of drawing a club is 13/52 or 1/4

But since the problem asks for drawing jack or club, therefore we should add the 2 probabilities, making 17/52. This is not the final answer yet. We know that there is a jack of clubs, therefore we need to subtract 1 from the probabilities since jack of clubs were considered in the 2 categories of probability.

With that being said, the probability of drawing a club or a jack is 16/52 or 4/13

Bonus Question:

The first thing you need to do here is find the probability of each scenario. First let's do what is given, the probability of drawing 2 aces. Since there are 4 aces in a deck of 52, we can easily say that the probability of drawing an ace is 4/52. However for our second draw, the probability of drawing a different ace is 3/51. This is so since we already drew a card that is an ace, hence we need to subtract one from the total aces (4-1) and from the total cards in the deck (52-1). In getting the probability of drawing two aces, we need to multiply the said probabilities: 4/52 and 3/51, resulting to 1/221.

For the second scenario, the drawing of 2 red cards, we just use the same concept but in this, we are already considering the 2 red cards in the first scenario, therefore the chance of drawing a red on our first draw is 24/52. For our second, we just need to subtract one card, therefore 23/51. Multiply these two and we will get 46/221.

Now, the problem asks for the chance of drawing either 2 reds or 2 aces, therefore we add the probabilities of the 2 scenarios:
46/222 + 1/221 = 47/221

Summary:
First Scenario:
4/52 + 3/51 = 1/221
Second Scenario:
24/52 + 23/51 = 46/221
Chances of drawing 2 red cards or 2 aces:
1/221 + 46/221 = 47/221
7 0
3 years ago
Which one ??????? :(
LuckyWell [14K]

Answer:

D.

Step-by-step explanation:

4 0
3 years ago
Some wrench sets come in metric units and others come in standard units. A chart compares the measurements of a metric set of wr
pshichka [43]

Answer:

b

Step-by-step explanation:

4 0
4 years ago
Read 2 more answers
Simplify the following expression:<br><br> 7472
Rainbow [258]

Answer:

7^2

Step-by-step explanation:

i hope this helps :)

7 0
3 years ago
Read 2 more answers
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