You can show that 
by constructing a triangle.
Take two points, O(0, 0) and A(1, 0), and let B be the point on the unit circle such that the angle between the line segments OA and OB is 
radians.
Since both A and B lie on the circle, the line segments OA and OB both have length 1 (same as the circle's radius). We finish constructing the triangle by connect A and B.
Since OB and OA have the same length, triangle OAB is isosceles, but more than that, it's also equilateral. Why? Because the interior angles of any triangle always add to 
radians. We know one of the angles is radians, which leaves a contribution of 
radians between the remaining angles A and B. Angles A and B must be congruent (because OAB is isosceles), which means they also have measure radians.
Next, draw an altitude of the triangle through point B, and label the point where it meets the "base" OA, C. Since OAB is equilateral, the altitude BC is also a perpendicular bisector. That means OC has length 
, and by definition of 
we have
Answer:
x f(x) g(x)
1 15 3
2 16 4
3 15 5
4 12 6
5 7 7
6 0 8
f(x) = g(x) when x = 5
Step-by-step explanation:
f(x) = -x² + 4x + 12
f(1) = -(1)² + 4(1) + 12 = 15
f(2) = -(2)² + 4(2) + 12 = 16
f(3) = -(3)² + 4(3) + 12 = 15
f(4) = -(4)² + 4(4) + 12 = 12
f(5) = -(5)² + 4(5) + 12 = 7
f(6) = -(6)² + 4(6) + 12 = 0
g(x) = x + 2
g(1) = 1 + 2 = 3
g(2) = 2 + 2 = 4
g(3) = 3 + 2 = 5
g(4) = 4 + 2 = 6
g(5) = 5 + 2 = 7
g(6) = 6 + 2 = 8
Answer:
<h2>
1/64</h2>
Step-by-step explanation:
just took the test and got 100% :)
Have a nice day!!
- <em> Shadow</em>
The answer is option c (-1,0)
Solving the equation you get that the zeros of this are approximately
x ≈ -2.8019
x ≈ -1.4450
x ≈ 0.24698
Then the function has three real roots, but none of them is within the range (-1,0)
Below is a graph of the function.
