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2 years ago

This is a substitution problem

Mathematics

2 answers:

mrs_skeptik [129]2 years ago

6 0

They consists of equations and unknown variables. There are 4 PCs and 8 Mac in the room

<h3>System of equation</h3>

They consists of equations and unknown variables

Let the number of PCs be x

Let the number of Mac be y

If Mke has 12 computers, then;

x + y = 12

If there are two Macs for every PC in his classroom, then;

y = 2x

Substitute

x + 2x = 12

3x = 12

x = 4

Recall y = 2x

y = 2(4)

y = 8

There are 4 PCs and 8 Mac in the room

Learn more on system of equations here; brainly.com/question/14323743

#SPJ2

Ivanshal [37]2 years ago

6 0

Answer:4 PCs and 8 Macs

Step-by-step explanation:

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Solve for b 2 in A = h(b 1+b 2), if A = 16, h = 4, and b 1 = 3. b 2 =

hammer [34]

Answer:

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Step-by-step explanation:

A = h(b1 + b2)

Given:

A = 16

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2 years ago

The lengths and widths of two rectangles are proportional. One

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The width of the rectangle would be 6 times the first rectangle and the length would be 8 times the first rectangle.

<u>Explanation:</u>

Given:

Two rectangles are proportional.

Length and width of 1 rectangle = 6 : 8

Dimensions of the other rectangle = ?

Let length and width of the other rectangle be x : y

According to the question:

$\frac{6}{8} :\frac{x}{y}$

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So, the width of the rectangle would be 6 times the first rectangle and the length would be 8 times the first rectangle.

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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