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Semmy [17]
3 years ago
7

Please someone help me, if you don't know the answer don't comment at all.

Mathematics
2 answers:
JulijaS [17]3 years ago
7 0

Answer:

Part E

When reflected across x axis, your y coordinate will be negative and the x coordinate will be the same. ex.

(5,4) = (5,-4)

Part I

You would add 6 to the y coordinate and subtract 1 from the x coordinate

Part K

Chanels Sequence

Step-by-step explanation:

Vinvika [58]3 years ago
3 0

Answer:

Part E

When reflected across x axis, your y coordinate will be negative and the x coordinate will be the same. ex.

(5,4) = (5,-4)

Part I

You would add 6 to the y coordinate and subtract 1 from the x coordinate

Part K

Chanels Sequence

Step-by-step explanation:

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5a+5b=25 and -5a+5b=35
Alex_Xolod [135]

add the two equations together

5a+5b=25

-5a+5b=35

------------------

 0  + 10b =60

divide by 10

b=6

5a + 5b = 25

5a +5(6) = 25

5a +30 =25

subtract 30 from each side

5a =-5

divide by 5

a = -1

Answer (-1,6)

or a=-1 b=6

3 0
3 years ago
7. There are 3 times as many adventure books as comic books in a bookshop. If there are 879 adventure books in the bookshop, how
dsp73
HEYY ok so the first question (comic book one) is 2637 comic books.
5 0
3 years ago
In quadratic formula
lorasvet [3.4K]

x² - x - 12 = 0


x = \dfrac{-b \pm \sqrt{b^{2} - 4ac}}{2a}


a = 1, b = -1, c = -12

x = \dfrac{1 \pm \sqrt{(-1)^{2} - 4(1)(-12)}}{2(1)}


x = 4 or -3


Answer: 4 or -3

4 0
3 years ago
In March 2007, Business Week reported that at the top 50 business schools, students studied an average of 14.6 hours. You wonder
Rasek [7]

Answer:

The hypotheses used in this situation

H_0:\mu = 14.6

H_a:\mu \neq 14.6

Step-by-step explanation:

We are given that  Business Week reported that at the top 50 business schools, students studied an average of 14.6 hours.

Mean = \mu = 14.6

Claim : The amount UMSL students study is different from this 14.6 hour benchmark.

The hypotheses used in this situation

H_0:\mu = 14.6

H_a:\mu \neq 14.6

5 0
3 years ago
You saved $20,000.00 and want to diversify your monies. You invest 45% in a Treasury bond for 3 years at 4.35% APR compounded an
Maru [420]

Compound Interest

A total of $20,000 is invested in different assets.

45% is invested in a Treasury bond for 3 years at 4.35 APR compounded annually.

For this investment, the principal is P = 0.45*$20,000 = $9,000.

The compounding period is yearly, thus the interest rate is:

i = 4.35 / 100 = 0.0435

The duration (in periods) is n = 3

Calculate the final value with the formula:

M=P_{}(1+i)^n

Substituting:

\begin{gathered} M=\$9,000_{}(1+0.0435)^3 \\ M=\$9,000\cdot1.136259062875 \\ M=\$10,226.33 \end{gathered}

The second investment is a CD at 3.75% APR for 3 years compounded annually. The parameters for the calculations are as follows:

P = 15% of $20,000 = $3,000

i = 3.75 / 100 = 0.0375

n = 3

Calculating:

\begin{gathered} M=\$3,000_{}(1+0.0375)^3 \\ M=\$3,000\cdot1.116771484375 \\ M=\$3,350.31 \end{gathered}

The third investment is in a stock plan. The initial value of the investment is

P = 20% of $20,000 = $4,000

By the end of the first year, the stock plan increased by 8%, thus its value is:

M1 = $4000 * 1.2 = $4,800

By the end of the second year, the stock plan decreased by 4$, thus the value is:

M2 = $4,800 * 0.96 = $4,608

Finally, the stock plan increases by 6%, resulting in a final balance of:

M3 = $4,608 * 1.06 = $4,884.48

Finally, the last investment is in a savings account at 2.90% APR compounded annually for 3 years (not mentioned, but assumed).

P = $20,000 - $9,000- $3,000 - $4,000 = $4,000

i = 2.90 / 100 = 0.029

n = 3

Calculating:

\begin{gathered} M=\$4,000_{}(1+0.029)^3 \\ M=\$4,000\cdot1.089547389 \\ M=\$4,358.19 \end{gathered}

To summarize, the final balances for each type of investment at the end of the third year are:

Investment 1; $10,226.33

Investment 2: $3,350.31

Investment 3: $4,884.48

Investment 4: $4,358.19

Total balance: $22,819.32

3 0
1 year ago
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