Divide the polygon into separate shapes. Like a rectangle and then a triangle.
find the areas of those shapes and then add them together.
Answer:
Tan C = 3/4
Step-by-step explanation:
Given-
∠ A = 90°, sin C = 3 / 5
<u>METHOD - I</u>
<u><em>Sin² C + Cos² C = 1</em></u>
Cos² C = 1 - Sin² C
Cos² C = 
Cos² C = 
Cos² C = 
Cos C = 
Cos C = 
As we know that
Tan C = 
<em>Tan C =
</em>
<em>Tan C =
</em>
<u>METHOD - II</u>
Given Sin C = 
therefore,
AB ( Height ) = 3; BC ( Hypotenuse) = 5
<em>∵ ΔABC is Right triangle.</em>
<em>∴ By Pythagorean Theorem-</em>
<em>AB² + AC² = BC²</em>
<em>AC² </em><em>= </em><em>BC² </em><em>- </em><em> AB</em><em>² </em>
<em>AC² = 5² - 3²</em>
<em>AC² = 25 - 9</em>
<em>AC² = 16</em>
<em>AC ( Base) = 4</em>
<em>Since, </em>
<em>Tan C =
</em>
<em>Tan C =
</em>
<em>Hence Tan C =
</em>
<em />
So i drew 12 circles and 37 circles
And i got 49 total:D
i hope this helps and sorry that the pic is wierd:(
Check the picture below.
so the lateral area will be just the area of the sides, namely excluding the bases at top and bottom, thus

6x - 31 = 11x + 64
6x cancels out and you take 6x away from 11x
-31 = 5x + 64
64 cancels out and you take 64 away from -31
-95 = 5x
Divide both sides by 5
-19 = x